
Which of the following exhibits linkage isomerism?
(A)- \[[Co{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]Br\]
(B)- \[[Co{{({{H}_{2}}O)}_{6}}]C{{l}_{3}}\]
(C)- \[[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})]C{{l}_{2}}\]
(D)- \[[Co{{(N{{H}_{3}})}_{6}}][Cr{{(CN)}_{6}}]\]
Answer
131.4k+ views
Hint: The coordination complexes that show linkage isomerism must have one special type of ligand which has two donor atoms, but only one of the donor atoms can bind to the central metal atom at a time.
Complete step by step solution:
- The coordination complexes that show linkage isomerism have ambidentate ligand.
- Ambidentate ligands are those which have two donor atoms, but only one of the donor atoms can bind to the central metal atom at a time.
- ‘Ambi’ means both and dentate means the denticity of the ligand.
- Denticity is the number of the donor atoms of the ligand that binds to the central metal atom in the coordination complex.
- Here, \[[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})]C{{l}_{2}}\]exhibits linkage isomerism.
\[N{{O}_{2}}\] is the ambidentate ligand in this coordination complex. This ligand is the reason the coordination complex shows the linkage isomerism.
When the central metal atom is bonded with nitrogen, the ligand is\[N{{O}_{2}}\]. When the metal atom is bonded with oxygen, the ligand is\[ONO\].
- Other examples of the ambidentate ligand are \[C{{N}^{-}}\]and\[N{{C}^{-}}\], \[SC{{N}^{-}}\]and\[NC{{S}^{-}}\].
- \[[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})]C{{l}_{2}}\]and \[[Co{{(N{{H}_{3}})}_{5}}(ONO)]C{{l}_{2}}\]are the linkage isomers.
So, option C is the correct option.
Additional Information:
Ligands can be monodentate, bidentate, and multidentate as well depending upon the number of the donor atoms of the ligand binding to the central metal atom.
Note \[N{{O}_{2}}\]is called a nitro ligand. When the donation is from the nitrogen to the metal center, it is nitro complex. The linkage of the ligand is as follow

\[ONO\]is called nitrito ligand. When the donation is from the nitrogen to the metal centre, it is nitrito complex. The linkage is as follows:

The complexes are octahedral in shape.
Complete step by step solution:
- The coordination complexes that show linkage isomerism have ambidentate ligand.
- Ambidentate ligands are those which have two donor atoms, but only one of the donor atoms can bind to the central metal atom at a time.
- ‘Ambi’ means both and dentate means the denticity of the ligand.
- Denticity is the number of the donor atoms of the ligand that binds to the central metal atom in the coordination complex.
- Here, \[[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})]C{{l}_{2}}\]exhibits linkage isomerism.
\[N{{O}_{2}}\] is the ambidentate ligand in this coordination complex. This ligand is the reason the coordination complex shows the linkage isomerism.
When the central metal atom is bonded with nitrogen, the ligand is\[N{{O}_{2}}\]. When the metal atom is bonded with oxygen, the ligand is\[ONO\].
- Other examples of the ambidentate ligand are \[C{{N}^{-}}\]and\[N{{C}^{-}}\], \[SC{{N}^{-}}\]and\[NC{{S}^{-}}\].
- \[[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})]C{{l}_{2}}\]and \[[Co{{(N{{H}_{3}})}_{5}}(ONO)]C{{l}_{2}}\]are the linkage isomers.
So, option C is the correct option.
Additional Information:
Ligands can be monodentate, bidentate, and multidentate as well depending upon the number of the donor atoms of the ligand binding to the central metal atom.
Note \[N{{O}_{2}}\]is called a nitro ligand. When the donation is from the nitrogen to the metal center, it is nitro complex. The linkage of the ligand is as follow

\[ONO\]is called nitrito ligand. When the donation is from the nitrogen to the metal centre, it is nitrito complex. The linkage is as follows:

The complexes are octahedral in shape.
Recently Updated Pages
Types of Solutions - Solution in Chemistry

JEE Main 2026 Syllabus PDF - Download Paper 1 and 2 Syllabus by NTA

A steel rail of length 5m and area of cross section class 11 physics JEE_Main

At which height is gravity zero class 11 physics JEE_Main

A nucleus of mass m + Delta m is at rest and decays class 11 physics JEE_MAIN

Two pi and half sigma bonds are present in A N2 + B class 11 chemistry JEE_Main

Trending doubts
JEE Main 2025 Session 2 Registration Open – Apply Now! Form Link, Last Date and Fees

Molar Conductivity

Raoult's Law with Examples

Chemistry Electronic Configuration of D Block Elements: JEE Main 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Salt Bridge

Other Pages
CBSE Date Sheet 2025 Class 12 - Download Timetable PDF for FREE Now

JEE Main 2025 - Session 2 Registration Open | Exam Dates, Answer Key, PDF

CBSE Class 10 Hindi Sample Papers with Solutions 2024-25 FREE PDF

CBSE Board Exam Date Sheet Class 10 2025 (OUT): Download Exam Dates PDF

CBSE Class 10 Hindi Course-B Syllabus 2024-25 - Revised PDF Download

SST Syllabus Class 10 CBSE 2024-25 Revised PDF Download
