Which of the following is the correct order of magnitude of various elastic moduli in materials like aluminium and copper?
(A) Young’s moduli < Shear moduli < Bulk moduli
(B) Bulk moduli < Shear moduli < Young’s moduli
(C) Shear moduli < Young’s moduli < Bulk moduli
(D) Bulk modulus < Young’s moduli < Shear moduli
Answer
Verified
116.4k+ views
Hint: In the stress – strain curve, the region which is in elastic limit describes the maximum stress the material will take before deforming permanently. The ratio between stress and strain is the modulus of elasticity. Elastic moduli are of three types – Young’s modulus, Shear modulus and Bulk modulus.
Complete step by step solution:
From the stress – strain curve, the region which is in elastic limit describes the maximum stress the material will take before deforming permanently. This region is important to manufacturing and structural sectors.
The elastic modulus can be defined as the ratio between stress and strain.
There are three types of elastic moduli:
Young’s modulus – Young’s modulus can be defined as the mechanical property to withstand the compression and elongation with respect to its length. It is denoted by $Y$. It quantifies the relationship between stress and strain. It is the measure of mechanical properties of linear elastic solids.
Shear modulus – This modulus can be defined as the ratio between shear stress and shar strain. It can be denoted by $\eta $. The S.I unit of shear modulus is pascals but it is generally expressed in gigapascals.
Bulk modulus – It is used to measure the resistance property of the substance. It describes how resistant to compression the substance is. It is denoted by $K$.
Now, the magnitude of various elastic moduli of copper are –
$
Y = 128 GPa \\
K = 140GPa \\
\eta = 48GPa \\
$
Therefore, for copper, Shear moduli < Young’s moduli < Bulk moduli
Hence, the correct option is (C).
Note: The Young’s modulus can describe the ability of the body to resist deformation on the application of force, so by using the value of Young’s modulus of the material we can also determine the rigidity of the body.
Complete step by step solution:
From the stress – strain curve, the region which is in elastic limit describes the maximum stress the material will take before deforming permanently. This region is important to manufacturing and structural sectors.
The elastic modulus can be defined as the ratio between stress and strain.
There are three types of elastic moduli:
Young’s modulus – Young’s modulus can be defined as the mechanical property to withstand the compression and elongation with respect to its length. It is denoted by $Y$. It quantifies the relationship between stress and strain. It is the measure of mechanical properties of linear elastic solids.
Shear modulus – This modulus can be defined as the ratio between shear stress and shar strain. It can be denoted by $\eta $. The S.I unit of shear modulus is pascals but it is generally expressed in gigapascals.
Bulk modulus – It is used to measure the resistance property of the substance. It describes how resistant to compression the substance is. It is denoted by $K$.
Now, the magnitude of various elastic moduli of copper are –
$
Y = 128 GPa \\
K = 140GPa \\
\eta = 48GPa \\
$
Therefore, for copper, Shear moduli < Young’s moduli < Bulk moduli
Hence, the correct option is (C).
Note: The Young’s modulus can describe the ability of the body to resist deformation on the application of force, so by using the value of Young’s modulus of the material we can also determine the rigidity of the body.
Recently Updated Pages
Uniform Acceleration - Definition, Equation, Examples, and FAQs
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Login 2045: Step-by-Step Instructions and Details
Class 11 JEE Main Physics Mock Test 2025
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Other Pages
NCERT Solutions for Class 11 Physics Chapter 7 Gravitation
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes - CBSE Physics Chapter 1
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
NCERT Solutions for Class 11 Physics Chapter 8 Mechanical Properties of Solids