Area of Triangle Using Determinant
Before understanding the determinant for finding the area of a triangle, let us have a quick look over the meaning of determinant first. So, the sum-product which is obtained by the elements of the square matrix is called a determinant. It helps to find the adjoint of the matrix, as well as the inverse of the matrix.
Now, finding the area of a triangle is not that difficult if the given triangle is a right-angle triangle, because the area of such a triangle can easily be found by finding the product, one-half, of the base and the height. But if the triangle is not the right-angle triangle, then finding the area of the triangle is not that easy.
Hence, there are few other methods of finding the area in such cases and one such method is finding the area of a triangle using the determinants.
The determinant is the scalar value which is computed from different elements of a square matrix that has certain properties of a linear transformation. Let us now learn how to use the determinant to find the area of a triangle. Let’s say that (x1, y1), (x2, y2 ), and ( x3, y3 ) are three points of the triangle in the cartesian plane.
Now the area of the triangle of the will be given as:
k = ½ [ x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ) ]
Here, k is the area of the triangle using determinant and the vertices of the triangle are represented by (x1, y1), (x2, y2 ), and ( x3, y3 ).
(Image will be uploaded soon)
In order to find the area of a triangle in determinant form, you use the formula given below:
K = ½ \[\begin{bmatrix} x_{1} & y_{1} & 1\\ x_{2} & y_{2} & 1 \\ x_{3} & y_{1} & 1\end {bmatrix}\]
The value of the determinant is either positive or negative but since here we are talking about the area of the triangle, we cannot have a negative value. Hence, we take the positive and the negative value or the absolute value of the determinant.
In case we already know the area of the triangle or the area has been given in the equation, we can use both the positive values of the determinant and the negative value of the determinant. In case three points are colinear, then it forms a line and not a triangle and the area of the triangle that is enclosed in a straight line is equal to 0. Therefore, the value of the determinant to find the area of the triangle would also be equal to zero. Keeping the aforementioned statements in mind, let us use the determinant expansion techniques using minors and cofactors and try to expand the determinant which denotes the area of the triangle.
Hence,
k = ½ (x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ))
This is how you apply determinants to make the calculation of the determinant easy. Let us apply this to a matrix and understand the concept much better.
Solved Examples
1. Find the area of the triangle whose vertices are A ( 1, 1 ), B ( 4, 2 ), and C ( 3, 5)
Solution: Using the formula that we have previously learnt, we can find out the area of the triangle by joining the point given in the formula
K = ½ \[\begin{bmatrix} x_{1} & y_{1} & 1\\ x_{2} & y_{2} & 1 \\ x_{3} & y_{1} & 1\end {bmatrix}\]
When you substitute the given values in the above formula, we get:
K = ½ \[\begin{bmatrix} 1 & 1 & 1\\ 4 & 2 & 1 \\ 3 & 5 & 1\end {bmatrix}\]
k = ½ (1 ( 2 - 5 ) - 4 ( 4 - 3 ) + 3 ( 20 - 3 ))
k = ½ (1 ( -3 ) -4 ( 1 ) + 3 ( 17 ))
k = ½ (- 3 - 4 + 51)
k = ½ (44)
k = 22 units.
Since the area of the triangle cannot be negative, the value of k = 3 units.
2. Find the area of a triangle by determinant method whose vertices are A ( 4, 9 ), B ( - 3, 3 ), and C ( 6, 2 )
Solution: Using the formula that we have previously learnt, we can find out the area of the triangle by joining the point given in the formula
K = ½ \[\begin{bmatrix} x_{1} & y_{1} & 1\\ x_{2} & y_{2} & 1 \\ x_{3} & y_{1} & 1\end {bmatrix}\]
When you substitute the given values in the above formula, we get:
K = ½ \[\begin{bmatrix} 4 & 9 & 1\\ -3 & 3 & 1 \\ 6 & 2 & 1\end {bmatrix}\]
k = ½ (4 ( 3 - 2) - 9 ( -3 - 6 ) + 1 ( - 6 - 18 ))
k = ½ (4 ( 1 ) - 9 ( - 9 ) +1 ( - 24 ))
k = ½ (4 + 81 - 24)
k = ½ (61)
k = 61 / 2 units
3. Find the area of the triangle whose vertices are A ( 4, 8 ), B ( - 6, 2 ), and C ( 5, 7 )
Solution: Using the formula that we have previously learnt, we can find out the area of the triangle by joining the point given in the formula
K = ½ \[\begin{bmatrix} x_{1} & y_{1} & 1\\ x_{2} & y_{2} & 1 \\ x_{3} & y_{1} & 1\end {bmatrix}\]
When you substitute the given values in the above formula, we get:
K = ½ \[\begin{bmatrix} 4 & 8 & 1\\ -6 & 2 & 1 \\ 5 & 7 & 1\end {bmatrix}\]
k = ½ (4 ( 2 - 7 ) - 8 ( - 6 - 5 ) + 1 ( - 42 - 10 ))
k = ½ (4 ( - 5 ) - 8 ( - 11 ) +1 ( - 52 ))
k = ½ (20 + 88 - 52)
k = ½ (56)
k = 28 units
FAQs on Determinant to Find the Area of a Triangle
1. How do you calculate the area of a triangle with the determinant?
Let’s say that (x1, y1), (x2, y2 ), and ( x3, y3 ) are three points of the triangle in the cartesian plane. Now the area of the triangle of the will be given as:
k = ½ (x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ))
Here, k is the area of the triangle and the vertices of the triangle are represented by: (x1, y1), (x2, y2 ), and ( x3, y3 ).In order to find the are of the triangle with the help of a determinant, you use the formula given below:
(Image will be uploaded soon)
The value of the determinant is either positive or negative but since here we are talking about the area of the triangle, we cannot have a negative value. Hence, we take the positive value or the absolute value of the determinant that is obtained. In case we already know the area of the triangle or the area has been given in the equation
2. What is the area and perimeter of a triangle?
The size or the surface of the triangle, or the measurement of the surface of the triangle is referred to as the area of the triangle. In simple terms, it means the amount of space covered by the triangles.
While on the other hand, the perimeter is the distance of the lines of the triangles, that is to say, that distance of the edges of the triangle is referred to as the perimeter of triangles. If you know the perimeter then it becomes easy for you to measure the area of the triangle.
3. What is Heron’s formula to find the area of a triangle?
Heron’s formula is one of the methods to find the area of triangles. The name of this formula is derived from the Hero of Alexandria and therefore it is also known as Hero’s formula.
For finding the area of triangles by this method, you must first know the lengths of all the three sides of the triangles, and what makes it different from the other methods of finding the area of triangles is that you are not required to find the angle of the triangle. The formula is s = 1/2 ( a + b + c ).
