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Hint: Furanose is a collective term for carbohydrates that represents a chemical structure including a five-membered ring system consisting of four carbon atoms and one oxygen atom. Chemically furanose is a cyclic hemiacetal of an aldopentose or a cyclic hemiketal of a ketohexose.
Complete answer:
-Furanose ring consists of four carbon and one oxygen atom having an anomeric carbon to the right of the oxygen atom. The highest numbered chiral carbon determines whether the structure will have D-configuration or L-configuration.
-Furanose with an L-configuration has the substituent on the highest numbered chiral carbon which is pointed downwards out of the plane and in a D-structure furanose, the highest-numbered chiral carbon is facing upwards.
-Depending on the direction of anomeric hydroxyl group pointing, the furanose ring will either have alpha or beta configuration. In a D-configuration of furanose, if the hydroxyl group is pointing down then it is an alpha configuration and if the hydroxyl group pointing up then it is a beta configuration. Similarly, it is opposite with respect to an L-configuration.
-For converting a Fisher projection to a Haworth projection, we will follow the following steps-
(i) You first need to number carbons and draw in the Fisher stereochemistry.
(ii) Now, rotate the molecule to $90{}^\circ $ in clockwise direction.
(iii) Next step is the bond rotation of ${{C}_{4}}$with ${{C}_{5}}$.
(iv) Last step is the closure of fischer projection forming a closed ring structure.
(2) In the next part of the question, we are asked to write Fisher projection of $\alpha -D$Ribulofuranose.
Note:
For D-sugars, the last carbon will end up at the top of the Haworth projection. For L-sugars, the last carbon will end up on the top of the Haworth projection. At ${{C}_{1}}$ for D-sugars, if the OH group is down then it is an alpha-anomer whereas if the OH group is up then it is a beta-anomer.
Complete answer:
-Furanose ring consists of four carbon and one oxygen atom having an anomeric carbon to the right of the oxygen atom. The highest numbered chiral carbon determines whether the structure will have D-configuration or L-configuration.
-Furanose with an L-configuration has the substituent on the highest numbered chiral carbon which is pointed downwards out of the plane and in a D-structure furanose, the highest-numbered chiral carbon is facing upwards.
-Depending on the direction of anomeric hydroxyl group pointing, the furanose ring will either have alpha or beta configuration. In a D-configuration of furanose, if the hydroxyl group is pointing down then it is an alpha configuration and if the hydroxyl group pointing up then it is a beta configuration. Similarly, it is opposite with respect to an L-configuration.
-For converting a Fisher projection to a Haworth projection, we will follow the following steps-
(i) You first need to number carbons and draw in the Fisher stereochemistry.
(ii) Now, rotate the molecule to $90{}^\circ $ in clockwise direction.
(iii) Next step is the bond rotation of ${{C}_{4}}$with ${{C}_{5}}$.
(iv) Last step is the closure of fischer projection forming a closed ring structure.
(2) In the next part of the question, we are asked to write Fisher projection of $\alpha -D$Ribulofuranose.
Note:
For D-sugars, the last carbon will end up at the top of the Haworth projection. For L-sugars, the last carbon will end up on the top of the Haworth projection. At ${{C}_{1}}$ for D-sugars, if the OH group is down then it is an alpha-anomer whereas if the OH group is up then it is a beta-anomer.
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