Answer
Verified
414k+ views
Hint: As given that a boy runs around a rectangular field and the length and breadth of rectangular field is given in the question. The distance covered by the boy is equal to the perimeter of the rectangular field. So, we calculate the perimeter of the rectangular field by using the formula
$\begin{align}
& \text{Perimeter}=2\left( l+b \right), \\
& \text{where, }l=length \\
& b=breadth \\
\end{align}$
Complete step-by-step solution:
We have been given that a boy runs around a rectangular field and the length of the rectangular field is $35m$ and breadth is $20m$.
The rectangular field is shown in the figure below:
We have to find the distance covered by the boy.
Now, the boy runs around the rectangular field, so the distance covered by the boy is equal to the perimeter of the rectangular field.
We know that perimeter of the rectangle is given by
$\begin{align}
& \text{Perimeter}=2\left( l+b \right) \\
& \text{where, }l=length \\
& b=breadth \\
\end{align}$
We have
$\begin{align}
& l=35 \\
& b=20 \\
\end{align}$
Now, substituting the values in the formula and simplifying further, we get
$\begin{align}
& \text{Perimeter}=2\left( 35+20 \right) \\
& \text{Perimeter}=2\left( 55 \right) \\
& \text{Perimeter}=110m \\
\end{align}$
We have the perimeter of the rectangle equal to $110m$.
So, the distance covered by the boy is $110m$.
Note: Perimeter of the rectangle is the total distance covered by its boundaries in two dimensional shapes. In this question given that the boy runs along boundaries so we calculate the perimeter instead of calculating the area of the rectangle. We can also find the perimeter of the rectangle by adding all four sides of the rectangle.
$\begin{align}
& \text{Perimeter}=2\left( l+b \right), \\
& \text{where, }l=length \\
& b=breadth \\
\end{align}$
Complete step-by-step solution:
We have been given that a boy runs around a rectangular field and the length of the rectangular field is $35m$ and breadth is $20m$.
The rectangular field is shown in the figure below:
We have to find the distance covered by the boy.
Now, the boy runs around the rectangular field, so the distance covered by the boy is equal to the perimeter of the rectangular field.
We know that perimeter of the rectangle is given by
$\begin{align}
& \text{Perimeter}=2\left( l+b \right) \\
& \text{where, }l=length \\
& b=breadth \\
\end{align}$
We have
$\begin{align}
& l=35 \\
& b=20 \\
\end{align}$
Now, substituting the values in the formula and simplifying further, we get
$\begin{align}
& \text{Perimeter}=2\left( 35+20 \right) \\
& \text{Perimeter}=2\left( 55 \right) \\
& \text{Perimeter}=110m \\
\end{align}$
We have the perimeter of the rectangle equal to $110m$.
So, the distance covered by the boy is $110m$.
Note: Perimeter of the rectangle is the total distance covered by its boundaries in two dimensional shapes. In this question given that the boy runs along boundaries so we calculate the perimeter instead of calculating the area of the rectangle. We can also find the perimeter of the rectangle by adding all four sides of the rectangle.
Recently Updated Pages
Why Are Noble Gases NonReactive class 11 chemistry CBSE
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
Let x1x2xn be in an AP of x1 + x4 + x9 + x11 + x20-class-11-maths-CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE