
A colour blind male $(X^cY)$ marries a carrier female $(X^CX^c)$. Possible genotype of daughters will be______?
a. $X^cX^c$ only
b. $X^CX^C$ only
c. $X^CX^C$ and $X^cX^c$
d. $X^CX^c$ and $X^cX^c$
Answer
480k+ views
Hint: Colour blind is defined as the inability to see colour. It is a type of $X$ linked or sex-linked recessive disease where when both alleles have carrier recessive $X$ and a person gets affected by the disease if the person has the homozygous recessive alleles together in the same cell. It is typically referred to as congenital colour vision disorders.
Complete answer:
According to Mendel’s law of inheritance with together of the law of segregation, the law of independent assortment the combination of the alleles will take place $X^cY$ (man) mate with $X^CX^c$ (female) then the outcome of girl genotype will be Four alleles will be present:
$X^c, Y, X^C, X^c$
Possible outcomes will be :
$X^cX^C, X^cX^c, YX^C, YX^c$
From these combination daughter genotype can be :
$X^cX^C, X^cX^c$
Hence there are 50-50 chances that the child daughter can be colour blind as for being colour blind genotype present should be $X^cX^c$.
$X^CX^c$ daughter genotype will be the carrier of the disease, she can transfer the disease but will not get herself affected by the disease. Probability for a daughter child is 2:1.
Hence, the correct answer is option (D).
Note: Colour blindness is a disease where a person able to see colour is decreased, he/she won't be able to differentiate between the colour. A person with 100 percent colour-blindness is known as achromatopsia. The diagnostic method used for testing the disease is known as the Ishihara colour test. It is a common problem that affects around 1 in 12 men and 1 in 200 women.
Complete answer:
According to Mendel’s law of inheritance with together of the law of segregation, the law of independent assortment the combination of the alleles will take place $X^cY$ (man) mate with $X^CX^c$ (female) then the outcome of girl genotype will be Four alleles will be present:
$X^c, Y, X^C, X^c$
Possible outcomes will be :
$X^cX^C, X^cX^c, YX^C, YX^c$
From these combination daughter genotype can be :
$X^cX^C, X^cX^c$
Hence there are 50-50 chances that the child daughter can be colour blind as for being colour blind genotype present should be $X^cX^c$.
$X^CX^c$ daughter genotype will be the carrier of the disease, she can transfer the disease but will not get herself affected by the disease. Probability for a daughter child is 2:1.
Hence, the correct answer is option (D).
Note: Colour blindness is a disease where a person able to see colour is decreased, he/she won't be able to differentiate between the colour. A person with 100 percent colour-blindness is known as achromatopsia. The diagnostic method used for testing the disease is known as the Ishihara colour test. It is a common problem that affects around 1 in 12 men and 1 in 200 women.
Recently Updated Pages
Master Class 12 Social Science: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
The gas that burns in oxygen with a green flame is class 12 chemistry CBSE

The probability that a leap year will have only 52 class 12 maths CBSE

Describe the poetic devices used in the poem Aunt Jennifers class 12 english CBSE

And such too is the grandeur of the dooms We have imagined class 12 english CBSE

What does the god that failed refer to class 12 english CBSE

Which country did Danny Casey play for class 12 english CBSE
