Answer
Verified
358.5k+ views
Hint: As mentioned in the question, a cylindrical vessel has to be tin-coated on its both sides i.e., a vessel has to be coated inside and outside. That means the area which has to be coated is doubled now. Here, it mentioned that the vessel is without a lid, so we will find the area of base (which is in the shape of a circle) and the lateral surface area of the cylinder. After calculating the area we can find out the cost of tin-coating.
Formula used:
Lateral surface area of cylinder = $2\pi rh$
Area of circle = $\pi {r^2}$
Complete step-by-step solution:
Let us first draw a figure from the information provided in the question.
Radius of the base of a cylindrical vessel $\left( r \right)$ = $70cm$ and height $\left( h \right)$ = $1.4m$ = $140cm$
Total surface area (excluding upper lid) on both sides = 2(Area of lateral surface of cylindrical vessel) + 2(area of base)
Here we are coating both side(inside+outside of the vessel) that’s why we multiplying by 2 with expression.
$ \Rightarrow Area = 2\pi rh \times 2 + \pi {r^2} \times 2$
On multiplication, we get
$= 4\pi rh + 2\pi {r^2}$
Take $\pi r$ as common
$= \pi r\left( {4h + 2r} \right)$
On substituting the values of radius and height, we get
$= \dfrac{{22}}{7} \times 70\left[ {4 \times 140 + 70 \times 2} \right]c{m^2}$
$= 220\left[ {560 + 140} \right]c{m^2}$
On multiplication, we get
$ =220 \times 700c{m^2}$
$= 154000c{m^2}$
Rate of tin coating = \[Rs{\text{ }}3.50{\text{ }}per{\text{ }}1000{\text{ }}cm{\;^2}\]
Total cost = \[Rs{\text{ }}\dfrac{{154000 \times 3.50}}{{1000}}\]
Total cost = \[Rs{\text{ }}154 \times 3.50\]
Total cost = \[Rs{\text{ 539}}\]
Thus, the cost of tin-coating a cylindrical vessel without lid at the rate of $Rs.3.50$ per $1000c{m^2}$ is \[Rs{\text{ 539}}\].
Note: Here, an important point to note is we didn’t apply the total surface area of the cylinder because the cylindrical vessel is without a lid. Students should be careful about the unit. Calculation should be done in the same unit either in $m$ or $cm$. Take care of the calculations to be sure of the final answer.
Formula used:
Lateral surface area of cylinder = $2\pi rh$
Area of circle = $\pi {r^2}$
Complete step-by-step solution:
Let us first draw a figure from the information provided in the question.
Radius of the base of a cylindrical vessel $\left( r \right)$ = $70cm$ and height $\left( h \right)$ = $1.4m$ = $140cm$
Total surface area (excluding upper lid) on both sides = 2(Area of lateral surface of cylindrical vessel) + 2(area of base)
Here we are coating both side(inside+outside of the vessel) that’s why we multiplying by 2 with expression.
$ \Rightarrow Area = 2\pi rh \times 2 + \pi {r^2} \times 2$
On multiplication, we get
$= 4\pi rh + 2\pi {r^2}$
Take $\pi r$ as common
$= \pi r\left( {4h + 2r} \right)$
On substituting the values of radius and height, we get
$= \dfrac{{22}}{7} \times 70\left[ {4 \times 140 + 70 \times 2} \right]c{m^2}$
$= 220\left[ {560 + 140} \right]c{m^2}$
On multiplication, we get
$ =220 \times 700c{m^2}$
$= 154000c{m^2}$
Rate of tin coating = \[Rs{\text{ }}3.50{\text{ }}per{\text{ }}1000{\text{ }}cm{\;^2}\]
Total cost = \[Rs{\text{ }}\dfrac{{154000 \times 3.50}}{{1000}}\]
Total cost = \[Rs{\text{ }}154 \times 3.50\]
Total cost = \[Rs{\text{ 539}}\]
Thus, the cost of tin-coating a cylindrical vessel without lid at the rate of $Rs.3.50$ per $1000c{m^2}$ is \[Rs{\text{ 539}}\].
Note: Here, an important point to note is we didn’t apply the total surface area of the cylinder because the cylindrical vessel is without a lid. Students should be careful about the unit. Calculation should be done in the same unit either in $m$ or $cm$. Take care of the calculations to be sure of the final answer.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Harsha Charita was written by A Kalidasa B Vishakhadatta class 7 social science CBSE
Which are the Top 10 Largest Countries of the World?
Banabhatta wrote Harshavardhanas biography What is class 6 social science CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE