Answer
Verified
491.4k+ views
Hint: Here we will proceed by assuming each instalment, m and n as variables. Then we will use the concept of deferred annuity to find each instalment using the given rate of interest i.e. 12% and principal amount be Rs. 20,000.
Complete step-by-step answer:
Deferred annuity is an annuity which commences only after a lapse of some specified time after the final purchase premium has been paid.
Formula of deferred annuity –
$p = \dfrac{a}{i}\dfrac{{{{\left( {1 + i} \right)}^n} - 1}}{{{{\left( {1 + i} \right)}^{m + n}}}}$
Here we will assume that each instalment will be a, m be the semi-annual instalment and n be the remaining instalments.
$ \Rightarrow $ m=7, n=3 and m + n=10,
Also given that p is Rs. 20,000
Now we will calculate i @ 12%,
$ \Rightarrow \dfrac{{12}}{{100}} \times \dfrac{1}{2} = 0.06$
So we will put the values of p, m + n and i in the formula,
$ \Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{{{\left( {1 + 0.06} \right)}^7} - 1}}{{{{\left( {1 + 0.06} \right)}^{10}}}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{{{\left( {1.06} \right)}^7} - 1}}{{{{\left( {1 + 0.06} \right)}^{10}}}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{1.503 - 1}}{{1.791}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{0.503}}{{1.791}}$
$\Rightarrow a = \dfrac{{20,000 \times 0.06 \times 1.791}}{{0.503}}$
$\Rightarrow a = \dfrac{{2149.2}}{{0.503}}$
$\therefore a = 427.76$
Hence each instalment is of Rs. 427.67.
Note: In order to solve this question, one mistake that many of us can do is we do not convert the given rate into i i.e. instalment. Also we must be careful about the semi-annual instalment in which m is semi-annual instalment and n is remaining seven instalments as one can get confused in this statement. Hence we will get the desired result.
Complete step-by-step answer:
Deferred annuity is an annuity which commences only after a lapse of some specified time after the final purchase premium has been paid.
Formula of deferred annuity –
$p = \dfrac{a}{i}\dfrac{{{{\left( {1 + i} \right)}^n} - 1}}{{{{\left( {1 + i} \right)}^{m + n}}}}$
Here we will assume that each instalment will be a, m be the semi-annual instalment and n be the remaining instalments.
$ \Rightarrow $ m=7, n=3 and m + n=10,
Also given that p is Rs. 20,000
Now we will calculate i @ 12%,
$ \Rightarrow \dfrac{{12}}{{100}} \times \dfrac{1}{2} = 0.06$
So we will put the values of p, m + n and i in the formula,
$ \Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{{{\left( {1 + 0.06} \right)}^7} - 1}}{{{{\left( {1 + 0.06} \right)}^{10}}}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{{{\left( {1.06} \right)}^7} - 1}}{{{{\left( {1 + 0.06} \right)}^{10}}}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{1.503 - 1}}{{1.791}}$
$\Rightarrow 20,000 = \dfrac{a}{{0.06}} \times \dfrac{{0.503}}{{1.791}}$
$\Rightarrow a = \dfrac{{20,000 \times 0.06 \times 1.791}}{{0.503}}$
$\Rightarrow a = \dfrac{{2149.2}}{{0.503}}$
$\therefore a = 427.76$
Hence each instalment is of Rs. 427.67.
Note: In order to solve this question, one mistake that many of us can do is we do not convert the given rate into i i.e. instalment. Also we must be careful about the semi-annual instalment in which m is semi-annual instalment and n is remaining seven instalments as one can get confused in this statement. Hence we will get the desired result.
Recently Updated Pages
A particle is undergoing a horizontal circle of radius class 11 physics CBSE
A particle is thrown vertically upwards with a velocity class 11 physics CBSE
A particle is rotated in a vertical circle by connecting class 11 physics CBSE
A particle is projected with a velocity v such that class 11 physics CBSE
A particle is projected with a velocity u making an class 11 physics CBSE
A particle is projected vertically upwards and it reaches class 11 physics CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Who was the leader of the Bolshevik Party A Leon Trotsky class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Which is the largest saltwater lake in India A Chilika class 8 social science CBSE
Ghatikas during the period of Satavahanas were aHospitals class 6 social science CBSE