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Hint:In the above mentioned question we will get to know about the nuclide as well as stable and unstable nuclide, also we will get to know that which nuclides are radioactive .And also we will discuss about nuclide $U_{92}^{238}$.
Complete step by step answer:
A nuclide is an atom that has a specific number of protons and neutrons in its nucleus.Nuclides are classified as either stable or unstable. There are $256$ stable nuclides among the $3100$ known nuclides that have never been observed to decay.Radionuclides are unstable nuclides that are radioactive. Radiogenic nuclides are the degradation products of their daughters.
Nuclides of the same atomic number. The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons). In \[92{\text{ }}U{\text{ }}238,\], there are \[92\] protons, \[92\] electrons,
$\text{neutrons}$ = \[238 - 92 = {\text{ }}146\]
$\Rightarrow \text{nucleons} = p{\text{ }} + {\text{ }}n{\text{ }}$
$\Rightarrow \text{nucleons} = {\text{ }}92 + {\text{ }}146{\text{ }}$
$\therefore \text{nucleons} = {\text{ }}238$
So, the nuclide $U_{92}^{238}$ has all the following except \[92\] neutrons.
Note:Stable nuclides are non-radioactive nuclides that, unlike radionuclides, do not undergo spontaneous radioactive decay. Stable isotopes are the terms used to describe certain nuclides in relation to particular elements.
Complete step by step answer:
A nuclide is an atom that has a specific number of protons and neutrons in its nucleus.Nuclides are classified as either stable or unstable. There are $256$ stable nuclides among the $3100$ known nuclides that have never been observed to decay.Radionuclides are unstable nuclides that are radioactive. Radiogenic nuclides are the degradation products of their daughters.
Nuclides of the same atomic number. The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons). In \[92{\text{ }}U{\text{ }}238,\], there are \[92\] protons, \[92\] electrons,
$\text{neutrons}$ = \[238 - 92 = {\text{ }}146\]
$\Rightarrow \text{nucleons} = p{\text{ }} + {\text{ }}n{\text{ }}$
$\Rightarrow \text{nucleons} = {\text{ }}92 + {\text{ }}146{\text{ }}$
$\therefore \text{nucleons} = {\text{ }}238$
So, the nuclide $U_{92}^{238}$ has all the following except \[92\] neutrons.
Note:Stable nuclides are non-radioactive nuclides that, unlike radionuclides, do not undergo spontaneous radioactive decay. Stable isotopes are the terms used to describe certain nuclides in relation to particular elements.
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