(a) Outline the relation between resistance and electrical resistivity of the material of a conductor in the shape of cylinder of length ‘l’ and therefore the area of cross section ‘A’. Thus derive the S.I unit of electrical resistivity.
(b) Resistance of a metal wire of length $5\,m$ is $100\Omega $. If the area of the cross section of the wire is $3 \times {10^{ - 7}}\,{m^2}$. Now calculate the resistivity of the metal.
Answer
Verified
411.9k+ views
Hint: Resistance is defined as the property of the conductor which opposes the flow of electric current. It is also defined as the ratio of the voltage applied to the electric current flowing through it.Resistivity is defined as the resistance offered by the material per unit length for unit cross-section. The SI unit of resistivity is Ohm.meter.
Complete step by step answer:
(a) Relation between resistance and electrical resistance within the form of cylinder of length $l$ and area of cross section $A$,
Then we get the formula,
$R = \dfrac{{\rho l}}{A}$
Where $R$ is resistance.
Now, $\rho = \dfrac{{AR}}{l} \to \left( 1 \right)$
currently substitute the units of $R, A$, and $l$, we get
where as, $R=\Omega $
$A={m^2}$ and $l=m$ then
$\Rightarrow \rho = \dfrac{{\Omega \times {m^2}}}{m} \\
\Rightarrow \rho = \Omega m \\ $
$\therefore \rho = \Omega - m$
(b) only if, resistance, R=$100\Omega $, Length $l=5\,m$ and area of cross section $A= 3 \times {10^{ - 7}}\,{m^2}$.
Now we will calculate the resistivity in metal by equation $\rho = \dfrac{{AR}}{l} \to (1)$
Substitute the particularly values with in the equation (1), then we tend to go
$\rho = \dfrac{{100 \times 3 \times {{10}^{ - 7}}}}{5}$
$\Rightarrow \rho = 0.000006\Omega - m \\
\therefore \rho = 6 \times {10^{ - 6}}\Omega - m \\$
Hence the resistivity of a metal is $6 \times {10^{ - 6}}\,\Omega - m$.
Note: Resistance physical phenomenon and related with synchrotron radiation that studies within the atomic layers of carbon. Property of an electric circuit system is ordinarily handling a lot of data apart from any channel in resistance. Hence the resistivity of a metal is $6 \times {10^{ - 6}}\Omega - m$.
Complete step by step answer:
(a) Relation between resistance and electrical resistance within the form of cylinder of length $l$ and area of cross section $A$,
Then we get the formula,
$R = \dfrac{{\rho l}}{A}$
Where $R$ is resistance.
Now, $\rho = \dfrac{{AR}}{l} \to \left( 1 \right)$
currently substitute the units of $R, A$, and $l$, we get
where as, $R=\Omega $
$A={m^2}$ and $l=m$ then
$\Rightarrow \rho = \dfrac{{\Omega \times {m^2}}}{m} \\
\Rightarrow \rho = \Omega m \\ $
$\therefore \rho = \Omega - m$
(b) only if, resistance, R=$100\Omega $, Length $l=5\,m$ and area of cross section $A= 3 \times {10^{ - 7}}\,{m^2}$.
Now we will calculate the resistivity in metal by equation $\rho = \dfrac{{AR}}{l} \to (1)$
Substitute the particularly values with in the equation (1), then we tend to go
$\rho = \dfrac{{100 \times 3 \times {{10}^{ - 7}}}}{5}$
$\Rightarrow \rho = 0.000006\Omega - m \\
\therefore \rho = 6 \times {10^{ - 6}}\Omega - m \\$
Hence the resistivity of a metal is $6 \times {10^{ - 6}}\,\Omega - m$.
Note: Resistance physical phenomenon and related with synchrotron radiation that studies within the atomic layers of carbon. Property of an electric circuit system is ordinarily handling a lot of data apart from any channel in resistance. Hence the resistivity of a metal is $6 \times {10^{ - 6}}\Omega - m$.
Recently Updated Pages
What percentage of the area in India is covered by class 10 social science CBSE
The area of a 6m wide road outside a garden in all class 10 maths CBSE
What is the electric flux through a cube of side 1 class 10 physics CBSE
If one root of x2 x k 0 maybe the square of the other class 10 maths CBSE
The radius and height of a cylinder are in the ratio class 10 maths CBSE
An almirah is sold for 5400 Rs after allowing a discount class 10 maths CBSE
Trending doubts
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE
Explain the Treaty of Vienna of 1815 class 10 social science CBSE
Write an application to the principal requesting five class 10 english CBSE