A plant with a genotype AaBb is crossed with a plant having the genotype aabb. The genotype of $F_1$ would be
A)AaBb,AABB
B)AaBb,aaBb
C)aaBB,AABb
D)AaBb,Aabb,aaBb,abab
Answer
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Hint: A test cross is an experiment conducted by the Mendel. A test cross is conducted to study the genetic trait of a pea plant. The main purpose to employ this is to determine the genetic makeup of the dominant organisms.
Complete answer:
A plant having a genotype AaBb is crossed with a plant with the genotype aabb. The genotype of $F_1$ would be AaBb, Aabb, aaBb, abab and this can be determined by the test cross. When the event individual with the homozygous recessive parent is crossed then this is called the test cross. that s cross is done to know if the first Filial generation is homozygous or heterozygous.
Additional Information: -The test cross is done to know whether a dominant phenotype is homozygous or heterozygous.
-In this, if the parent(unknown) is homozygous dominant then all the offspring produced will also express the dominant phenotype And if the parent (unknown) is heterozygous than half of the offspring produced will be dominant and half of the offspring will be recessive
-this cross is also done to know if the two genes are linked or unlinked when they are crossed with the known heterozygote.
-If the potential of the phenotype is in the equal ratio then genes are likely to be unlinked.
-If two phenotypes are present in a higher amount and to present in the lower amount then the genes are likely to be linked.
-To determine the statistical calculation of each scenario of the Chi-square test is used.
So, the correct answer is,"AaBb,Aabb,aaBb,abab".
Note: -For doing the test cross there is a large number of the requirement of offsprings to produce correct data for a meaningful conclusion.
-Due to the advancement of genetic screening and genome mapping test cross is not commonly used nowadays.
-The accurate data of the test cross depends on the presence of a large statistical sample.
Complete answer:
A plant having a genotype AaBb is crossed with a plant with the genotype aabb. The genotype of $F_1$ would be AaBb, Aabb, aaBb, abab and this can be determined by the test cross. When the event individual with the homozygous recessive parent is crossed then this is called the test cross. that s cross is done to know if the first Filial generation is homozygous or heterozygous.
Additional Information: -The test cross is done to know whether a dominant phenotype is homozygous or heterozygous.
-In this, if the parent(unknown) is homozygous dominant then all the offspring produced will also express the dominant phenotype And if the parent (unknown) is heterozygous than half of the offspring produced will be dominant and half of the offspring will be recessive
-this cross is also done to know if the two genes are linked or unlinked when they are crossed with the known heterozygote.
-If the potential of the phenotype is in the equal ratio then genes are likely to be unlinked.
-If two phenotypes are present in a higher amount and to present in the lower amount then the genes are likely to be linked.
-To determine the statistical calculation of each scenario of the Chi-square test is used.
So, the correct answer is,"AaBb,Aabb,aaBb,abab".
Note: -For doing the test cross there is a large number of the requirement of offsprings to produce correct data for a meaningful conclusion.
-Due to the advancement of genetic screening and genome mapping test cross is not commonly used nowadays.
-The accurate data of the test cross depends on the presence of a large statistical sample.
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