Question

A proton moves along a horizontal line and towards the observer. What will be the pattern of concentric circular field lines of magnetic field produced due to its motion?

Answer 1

Hint: In order to answer this question, we will discuss the pattern of concentric circular field lines of magnetic field produced due to its motion, by conserving a dotted line depicting a proton travelling to identify the direction.

Complete step by step answer:
A proton is a charged particle with a positive charge. It creates a circular field along its path as it moves in a horizontal plane. Consider a dotted line depicting a proton travelling up the page to identify the direction. If we suppose that the proton is travelling out, the magnetic field will be anti-clockwise and parallel to the observer's path, according to the right hand rule.

If the same current passes in both the cases, find the ratio of the magnetic field produced at the centres in the two cases two protons \[P{\text{ }}and{\text{ }}Q\] moving with a same speed enters magnetic field \[B_1\, and\,B_2\] respectively at right angles to the field direction. If \[B_1 > B_2\] , for which proton the circular path in the magnetic field has a smaller radius.

A charged particle with a charge of $q$ is travelling along the \[x - axis\] at a speed of $v$. It enters a region of space where there is both an electric field \[E\left( { = Ej} \right)\] and a magnetic field $B$ . When the particle emerges from this zone, it can only be seen travelling along the \[x - axis\].

Note: Since the proton has charge \[ + 1{\text{ }}e\] , it should have a magnetic moment equal to \[1\mu N\] by this expression. The fact that the proton has a greater magnetic moment suggests that it is not an elementary particle. The magnetic moment of the proton has the sign of a positively charged particle.