Question

A small pack of cards consists of the Ace, king, queen, jack and ten of all four suits. Find the probability of selecting the queen of spades.

Answer 1

Hint:
A standard deck of playing cards consists of \[52\] cards all cards are divided into 4 units. There are two black suits, spades and clubs and two red suits of heart and diamond. In each suit there are 13 cards including \[2,\,\,3,\,\,4,\,\,5,\,\,6,\,\,7,\,\,8,\,\,9,\,\,10\] a jack, a queen, a king and an ace.
Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur or how likely it is that a proposition is true. The probability of an event is a number between \[0\] and \[1\], where, roughly speaking, \[0\] indicates impossibility of the event and \[1\] indicates certainty.

 Complete step by step solution:
Given no. of queen cards \[ = 4\]
No. of jack cards \[ = 4\]
And 10 of all four suits \[ = 10\]
Now,
Total cards\[ = 4 + 4 + 4 + 4 + 40 = 52\] card
Selecting of queen of spades card \[ = 1\]
Probability of queen card \[ = \dfrac{1}{{52}}\]
So, the probability of selecting the queen of spades \[ = \dfrac{1}{{52}}\]or \[0.019\]

Note: There is no other option. It is a direct question of the probability of the queen of spades.
Since I find the probability of not a queen of spades. Since probability that a first card is Not queen of spade is \[\dfrac{{51}}{{52}}\]
Probability of queen of spade is
\[1 - \dfrac{{51}}{{52}} = \dfrac{1}{{52}}\]