
Alkaline hydrolysis of which among the following compounds leads to the formation of a racemate?
(A) 1-bromo-1-phenylethane
(B) 1-chloro-3-methylbutane
(C) Bromo ethane
(D) 1-chloropropane
Answer
489.3k+ views
Hint: The process of converting an optically active (d- or l-) compound refers to the racemization. This racemic modification is related to stereochemical aspects of nucleophilic substitution reactions. The relationship with haloalkanes and alkaline hydrolysis will be explained based on the racemization process.
Complete step by step answer:
Racemate or racemic mixture of a chiral compound that consists of a 50:50 mixture of two enantiomers and the racemization is to become a racemate.
The following reaction represents alkaline hydrolysis of haloalkanes will be:
Where R =alkyl group and X = halogens
Apply the above reaction to given haloalkanes,
(A) 1-Bromo-1-phenylethane reaction with alkaline KOH
(B) 1-chloro-3-methyl butane reaction with alkaline KOH
(C) Bromo ethane reacts with KOH,
(D) 1-chloro propane involves in alkaline hydrolysis
Since, the products of (B), (C), and (D) do not form Racemate because there is no chiral carbon atom in the products.
The product formed in reaction A having chiral carbon, this hydrolysis will lead to the formation of a racemate or racemic mixture.
Note: The conversation of half of its dextro form into levo form so that the mixture is optically inactive due to the presence of equal amounts of two enantiomers involves the racemization process. This process can be brought by the action of heat, chemical reagents, and autorecemisation. The thermodynamically favorable method is racemization and proceeds spontaneously if a suitable pathway is accessible for the interconversion of the enantiomers.
Complete step by step answer:
Racemate or racemic mixture of a chiral compound that consists of a 50:50 mixture of two enantiomers and the racemization is to become a racemate.
The following reaction represents alkaline hydrolysis of haloalkanes will be:
Where R =alkyl group and X = halogens
Apply the above reaction to given haloalkanes,
(A) 1-Bromo-1-phenylethane reaction with alkaline KOH

(B) 1-chloro-3-methyl butane reaction with alkaline KOH

(C) Bromo ethane reacts with KOH,
(D) 1-chloro propane involves in alkaline hydrolysis
Since, the products of (B), (C), and (D) do not form Racemate because there is no chiral carbon atom in the products.
The product formed in reaction A having chiral carbon, this hydrolysis will lead to the formation of a racemate or racemic mixture.
Note: The conversation of half of its dextro form into levo form so that the mixture is optically inactive due to the presence of equal amounts of two enantiomers involves the racemization process. This process can be brought by the action of heat, chemical reagents, and autorecemisation. The thermodynamically favorable method is racemization and proceeds spontaneously if a suitable pathway is accessible for the interconversion of the enantiomers.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Give 10 examples of unisexual and bisexual flowers

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

What are the major means of transport Explain each class 12 social science CBSE

Why is the cell called the structural and functional class 12 biology CBSE
