Answer
Verified
462.9k+ views
Hint:Here we have two charged particles one is proton and the other is an alpha particle and they both are moving in a straight line towards the positive x-axis. They enter a region of magnetic field perpendicularly and we need to fight the trajectory since they both are charged they will be acted upon by the magnetic force
Complete step by step answer:
The magnetic force on a charged particle placed in a magnetic field is given by \[\overrightarrow{F}=q(\overrightarrow{v}\times \overrightarrow{B})\]
The angle between the velocity vector and the magnetic field is \[90{}^\circ \], so the magnitude of the magnetic force will be,
$F=qvB$
The direction is given as \[=v\widehat{i}\times B(-\widehat{k})\].
Since we are interested in finding the direction, taking only unit vectors we get,
\[\begin{align}
& =\widehat{i}\times (-\widehat{k}) \\
& =\widehat{j} \\
\end{align}\]
So the force acts towards the positive y-axis that is in an upward direction for both the particles. Now let us find the magnitude for both of them. Since both have the same velocity and the value of the magnetic field is the same for both, F=qvB,
Force is directly proportional to the magnitude of charge and the charge on the alpha particle is twice the value of charge on the proton, so the force acting on the alpha particle will be two times in magnitude the force acting on the proton.
So the trajectory looks like,
Note:Proton has a charge q and the charge on the alpha particle which is a doubly ionized helium atom is 2q. Both are positive and when they enter the magnetic field, they experience the force. If the angle between the velocity vector and the magnetic field was zero, then both of them would have passed undeflected.
Complete step by step answer:
The magnetic force on a charged particle placed in a magnetic field is given by \[\overrightarrow{F}=q(\overrightarrow{v}\times \overrightarrow{B})\]
The angle between the velocity vector and the magnetic field is \[90{}^\circ \], so the magnitude of the magnetic force will be,
$F=qvB$
The direction is given as \[=v\widehat{i}\times B(-\widehat{k})\].
Since we are interested in finding the direction, taking only unit vectors we get,
\[\begin{align}
& =\widehat{i}\times (-\widehat{k}) \\
& =\widehat{j} \\
\end{align}\]
So the force acts towards the positive y-axis that is in an upward direction for both the particles. Now let us find the magnitude for both of them. Since both have the same velocity and the value of the magnetic field is the same for both, F=qvB,
Force is directly proportional to the magnitude of charge and the charge on the alpha particle is twice the value of charge on the proton, so the force acting on the alpha particle will be two times in magnitude the force acting on the proton.
So the trajectory looks like,
Note:Proton has a charge q and the charge on the alpha particle which is a doubly ionized helium atom is 2q. Both are positive and when they enter the magnetic field, they experience the force. If the angle between the velocity vector and the magnetic field was zero, then both of them would have passed undeflected.
Recently Updated Pages
A very dilute acidic solution of Cd2+ and Ni2+ gives class 12 chem sec 1 JEE_Main
Calculate the equivalent resistance between A and class 12 physics JEE_Main
The potential difference between points A and B in class 12 physics JEE_Main
A wire is bent in the form of a triangle now the equivalent class 12 physics NEET_UG
For the circuit shown in figure the equivalent capacitance class 12 physics JEE_Main
If on applying the potential of 20 V on a conductor class 12 physics JEE_Main
Trending doubts
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Explain sex determination in humans with the help of class 12 biology CBSE
How much time does it take to bleed after eating p class 12 biology CBSE
Distinguish between asexual and sexual reproduction class 12 biology CBSE