Answer
Verified
462.9k+ views
Hint: malus law is, when a plane-polarized light incident i.e. falls on the analyzer, then the intensity I of the transmitted light is found to be directly proportional to the square of the cosine of the angle between the axis of transmission of polarizer and analyzer.
Formula used:
$I = {I_0}{\cos ^2}\theta $
Where,
$I$=intensity of transmitted light
${I_0}$= intensity of incident light
$\theta $=angle between transmission axis of polarizer and analyzer.
Complete step by step solution:
Malus law states that the intensity of a beam of plane-polarized light after passing through a rotatable polarizer varies as the square of the cosine of the angle.
Mathematically given as below.
$I = {I_0}{\cos ^2}\theta $ (1)
Now, let us first write the information given in the question.
${I_0}$ =$32W{m^{ - 2}}$, intensity of final emerging light =$3W{m^{ - 2}}$.
We have to find the intensity of light transmitted by the first polarizer given below using Malus law from equation (1).
$I = {I_0}{\cos ^2}\theta $ (2)
Average value of cos2θ is ½.
Hence, equation (2) becomes,
$I = {I_0} \times \dfrac{1}{2}$
Now let us substitute the value of ${I_0}$ in the above equation.
$I = 32W{m^{ - 2}} \times \dfrac{1}{2}$
$ = 16W{m^{ - 2}}$
Therefore, the intensity of light transmitted by first polarizer is 16Wm-2.
Hence, option (B) is correct option.
Additional information:
When ‘
Θ=00 or 1800,
In such case, $I = {I_0}{\cos ^2}\theta $
⟹${I_0}{\cos ^2}{0^0}$
⇒${I_0}$
I.e. when the transmission axes of analyzer and polarizer are parallel to each other, then intensity of light transmitted from the analyzer is maximum.
When ‘
Θ=900,
In such case, $I = {I_0}{\cos ^2}\theta $
⟹${I_0}{\cos ^2}{90^0}$
⇒$0$
I.e. when the transmission axes of analyzer and polarizer are perpendicular to each other, then intensity of light transmitted from the analyzer is minimum.
Note:
Unpolarized light wave vibrates in more than one plane whereas polarized light wave vibrates in a single plane. The process of converting unpolarized light into polarized light is called polarization of light.
A polarizer is an optical device that converts unpolarized light into polarized light in some form.
The intensity of light is the power radiated per unit area where the area is measured plane perpendicular to the direction of propagation of energy. Its SI unit is \[W{m^{ - 2}}\].
Formula used:
$I = {I_0}{\cos ^2}\theta $
Where,
$I$=intensity of transmitted light
${I_0}$= intensity of incident light
$\theta $=angle between transmission axis of polarizer and analyzer.
Complete step by step solution:
Malus law states that the intensity of a beam of plane-polarized light after passing through a rotatable polarizer varies as the square of the cosine of the angle.
Mathematically given as below.
$I = {I_0}{\cos ^2}\theta $ (1)
Now, let us first write the information given in the question.
${I_0}$ =$32W{m^{ - 2}}$, intensity of final emerging light =$3W{m^{ - 2}}$.
We have to find the intensity of light transmitted by the first polarizer given below using Malus law from equation (1).
$I = {I_0}{\cos ^2}\theta $ (2)
Average value of cos2θ is ½.
Hence, equation (2) becomes,
$I = {I_0} \times \dfrac{1}{2}$
Now let us substitute the value of ${I_0}$ in the above equation.
$I = 32W{m^{ - 2}} \times \dfrac{1}{2}$
$ = 16W{m^{ - 2}}$
Therefore, the intensity of light transmitted by first polarizer is 16Wm-2.
Hence, option (B) is correct option.
Additional information:
When ‘
Θ=00 or 1800,
In such case, $I = {I_0}{\cos ^2}\theta $
⟹${I_0}{\cos ^2}{0^0}$
⇒${I_0}$
I.e. when the transmission axes of analyzer and polarizer are parallel to each other, then intensity of light transmitted from the analyzer is maximum.
When ‘
Θ=900,
In such case, $I = {I_0}{\cos ^2}\theta $
⟹${I_0}{\cos ^2}{90^0}$
⇒$0$
I.e. when the transmission axes of analyzer and polarizer are perpendicular to each other, then intensity of light transmitted from the analyzer is minimum.
Note:
Unpolarized light wave vibrates in more than one plane whereas polarized light wave vibrates in a single plane. The process of converting unpolarized light into polarized light is called polarization of light.
A polarizer is an optical device that converts unpolarized light into polarized light in some form.
The intensity of light is the power radiated per unit area where the area is measured plane perpendicular to the direction of propagation of energy. Its SI unit is \[W{m^{ - 2}}\].
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE