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What is the angle between the reflected ray and the refracted ray when an ordinary ray of light is incident on a transparent medium at polarizing angle?

Answer
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Hint The angle between the reflected ray and the refracted ray is always 90 , when a ray of light is incident on a transparent medium at polarizing angle. This can be derived from Brewster’s law.

 Complete step-by-step solution:
The angle of incidence at which a fully plane polarised light is perfectly transmitted through a transparent dielectric surface, with no reflection is known as the polarizing angle (also called Brewster's angle).
We can better understand the polarizing angle with the help of Brewster's Law which states that when an ordinary unpolarised light is incident at an angle of polarization (ip) on the boundary separating air from a medium of refractive index μ , then reflected light becomes fully polarized and the tangent of the angle of polarization is numerically equal to the refractive index of the medium i.e. μ=tanip ….(i)

Now, from Snell’s law we can say that μ=sinipsinr …..(ii) where r is the angle of refraction in denser medium.
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Now, from equations (i) and (ii), we have
tanip=sinipsinr
On further solving we have
cosip=sinr
Now as we know, cosθ=sin(90θ)
So, sin(90ip)=sinr
On simplification we have
ip+r=90
Now, as clear from the diagram that if ip+r=90 then the angle between reflected ray and refracted ray will be 18090=90 .
Hence, when a ray of light is incident on a transparent medium at polarizing angle then the angle between the reflected ray and the refracted ray is 90 .

Note:Snell’s law is defined as the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color and for the given pair of media.
Brewster’s window is an application of Brewster's law and Brewster's angle. It is a window made up of glass which transmits 100% of light. These windows are used in gas lasers and in solid state lasers.
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