Question

What are A and B? $$\text{C}{\text{H}}_{\text{3}}\text{C}{\text{H}}_{\text{2}}\text{OH}\stackrel{\text{[O]}}{\to }\text{A}\underset{{\text{H}}_{\text{2}}\text{O/}{\text{H}}^{\text{ + }}}{\overset{\text{C}{\text{H}}_{\text{3}}\text{MgI}}{\to }}\text{B}$$

Answer 1

Hint: In order to find A and B, we must know what will be formed when primary alcohol undergoes oxidation. After finding A, it will be easy to find what will be formed when the Grignard reagent reacts with A.

Complete Solution :
Let us now move on to the problem.
The given primary alcohol (i.e. Ethanol) which on oxidation will give compound A, which is an aldehyde. The obtained aldehyde is an acetaldehyde. The reaction is given below:

This acetaldehyde in reaction with the Grignard reagent and $$H_{2}O/H^{+}$$, we will get secondary alcohol. The obtained secondary alcohol is Isopropyl alcohol. The reaction is given below:

 Therefore, the correct answer is
A- Acetaldehyde
B- Isopropyl alcohol

Additional information:
There are different aldehydes such as benzaldehyde, acetaldehyde, formaldehyde, etc which can be used for different purposes such as
- formaldehyde with 40% of water will form formalin. This formalin can be used to preserve the specimens.
- Acetaldehyde can be used in the synthesis of acetic acid.
- Acetaldehyde is also used to produce pyridine derivatives.
- Benzaldehydes is used in dyes, cosmetic products and perfumes.
- Formaldehyde when reacted with phenol, it forms Bakelite. Bakelite used in switch boards, plastics, etc.

Note: - Secondary alcohol on oxidation with $$KMn{O}_4$$, we will get ketone.
- The formed acetaldehyde on further oxidation we will be getting acetic acid.
- Aldehyde on reduction with $$LiAl{H}_4$$ we would get primary alcohol.