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Arrange in ascending order : 12,098 ; 12,908 ; 12,809 ; 12,890
A) 12,098 ; 12,908 ; 12,809 ; 12,890
B) 12,098 ; 12,809 ; 12,890 ; 12,908
C) 12,098 ; 12,890 ; 12,908 ; 12,809
D) 12,890 ; 12,908 ; 12,809 ; 12,098

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Last updated date: 20th Sep 2024
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Answer
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Hint:
With the given set of numbers, we need to arrange them from small to big. For arranging them we need to check whether all the numbers have the same highest place value and checking the digits of the number one by one we can arrange them in the required order.

Complete step by step solution:
We are given a set of numbers
They are 12,098 ; 12,908 ; 12,809 ; 12,890
We are asked to arrange them in ascending order. Arranging the numbers from small to big is known as ascending order. At first we need to highest place value of the given numbers
We can see that the highest place value of all the numbers is ten lakhs. So we can go to the next step. Now let's check the first number of all the numbers and we can see that all the numbers start with 1. So now let's check the second number and we can see that all the numbers start with 2. Now checking the third digit we need to select the number with the smallest third digit. The number with the least third digit here is 12,098.
Hence we place it first
12,098 ; 12,908 ; 12,809 ; 12,890
The numbers with the second least third digit is 12,809 ; 12,890
Since we have two numbers we need to check the fourth digit of the numbers. We can see that 12,809 has the least fourth digit.
We place it second and 12,890 third.

12,098 ; 12,809 ; 12,890 ; 12,908
Hence we get the required order.


Note:
1) Numbers are said to be in descending order when they are arranged from the largest to the smallest number.
2) Whenever we arrange it in descending order we first need to check the first number of all the numbers and select the number which is big and we need to repeat the same process in the reverse way.