Question

Arrange the following electromagnetic radiations per quantum in order of increasing energy:
A: Blue light
B: Yellow light
C: X-ray
D: Radiowave
A. D,B,A,C
B. A,B,D,C
C. C,A,B,D
D. B,A,D,C

Answer 1

Hint: In the electromagnetic spectrum, we have wavelength increasing from left to right and frequency increasing from right to left. The energy of the radiation is directly proportional to the frequency and inversely proportional to the wavelength. Using this information from electromagnetic spectrum, we can identify the correct answer

Complete answer:
The electromagnetic spectrum gives us arrangement of various electromagnetic radiation based on their frequency and wavelength. All the electromagnetic radiations are arranged in order of wavelength or frequency.
It is given as follows: The electromagnetic spectrum consists of gamma rays, x-rays, ultraviolet rays, visible rays, infrared rays, microwaves and radio waves in the order of increasing wavelength and decreasing frequency of the radiation.
The energy of a quantum of a given radiation is given in terms of the wavelength and/or frequency of the radiation by the following expression.
\[E = h\nu = \dfrac{{hc}}{\lambda }\]
Here $\nu $ is the frequency of the electromagnetic radiation, $\lambda $ represents the wavelength of the radiation while c is the speed of light with which the radiation travels.
So, the energy of the radiation is directly proportional to the frequency and inversely proportional to the wavelength.
Based on this, radio waves have less energy, yellow has greater energy than radio waves, blue light and x-rays have the highest energy.

So, the correct answer is “Option A”.

Note:
Since the frequency of electromagnetic radiation is directly related to the frequency of the radiation, therefore, the gamma rays possess highest energy because of the largest frequency and the smallest wavelength while the radio waves have least energy since they have the largest wavelength and the smallest frequency.