Answer
Verified
400.5k+ views
Hint :Resonance: The delocalization of $ \pi $ bond within the molecule or compound to form different canonical structures is known as resonance. It is the major factor due to which a molecule gains stability.
Complete Step By Step Answer:
Nitrous oxide i.e., $ {N_2}O $ is a non-flammable and colourless gas which is sweet in taste. It is also called laughing gas.
The two structures given for nitrous oxide are given as follows:
(i)
(ii)
As, the second structure is more stable than the first structure, so the assertion statement is correct.
The second structure is more stable than the first structure because of the arrangement of charges on the atoms on the basis of the electronegativity. In structure $ (i) $ , the negative charge is on the nitrogen atom which is a less electronegative element whereas in structure $ (ii) $ , the negative charge is on the oxygen atom which is the highly electronegative and a positive charge on the nitrogen atom which is comparatively less electronegative. Hence, the structure $ (ii) $ forms a more stable canonical structure than $ (i) $ and therefore more stable.
The reason statement given in the question is incorrect because both the structures of nitrous oxide are showing resonance. Here, the stability varies on the most stable canonical structure.
Hence, option (C) is the correct answer.
Note :
Canonical structures are also called resonance hybrids. The most stable canonical structures are those in which the most electronegative element is negatively charged and an atom which is comparatively less electronegative has a positive charge.
Complete Step By Step Answer:
Nitrous oxide i.e., $ {N_2}O $ is a non-flammable and colourless gas which is sweet in taste. It is also called laughing gas.
The two structures given for nitrous oxide are given as follows:
(i)
(ii)
As, the second structure is more stable than the first structure, so the assertion statement is correct.
The second structure is more stable than the first structure because of the arrangement of charges on the atoms on the basis of the electronegativity. In structure $ (i) $ , the negative charge is on the nitrogen atom which is a less electronegative element whereas in structure $ (ii) $ , the negative charge is on the oxygen atom which is the highly electronegative and a positive charge on the nitrogen atom which is comparatively less electronegative. Hence, the structure $ (ii) $ forms a more stable canonical structure than $ (i) $ and therefore more stable.
The reason statement given in the question is incorrect because both the structures of nitrous oxide are showing resonance. Here, the stability varies on the most stable canonical structure.
Hence, option (C) is the correct answer.
Note :
Canonical structures are also called resonance hybrids. The most stable canonical structures are those in which the most electronegative element is negatively charged and an atom which is comparatively less electronegative has a positive charge.
Recently Updated Pages
A wire of length L and radius r is clamped rigidly class 11 physics JEE_Main
For which of the following reactions H is equal to class 11 chemistry JEE_Main
For the redox reaction MnO4 + C2O42 + H + to Mn2 + class 11 chemistry JEE_Main
In the reaction 2FeCl3 + H2S to 2FeCl2 + 2HCl + S class 11 chemistry JEE_Main
One mole of a nonideal gas undergoes a change of state class 11 chemistry JEE_Main
A stone is projected with speed 20 ms at angle 37circ class 11 physics JEE_Main
Trending doubts
Which is the longest day and shortest night in the class 11 sst CBSE
Who was the Governor general of India at the time of class 11 social science CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
State and prove Bernoullis theorem class 11 physics CBSE