Answer
Verified
446.7k+ views
Hint: The astronomical unit is a unit of length, roughly the distance from earth to the sun and equal about $150$million kilometers. The actual distance varies as earth orbits the sun, from a maximum to a minimum and back again once each year.
Complete step by step answer:
We convert meters to astronomical unit, and seconds to minutes, using
$ 1000m = 1km \\
1AU = 1.50 \times {10^8}km \\
60s = 1\min \\
$
Thus, $3.0 \times {10^8}m/s$becomes
$\left( {\dfrac{{3.0 \times {{10}^8}m}}{8}} \right)\left( {\dfrac{{1km}}{{1000m}}} \right)\left( {\dfrac{{60s}}{{\min }}} \right) = 0.12AU/\min $
Astronomical unit: a unit of measurement equal to $149.6$million kilometers, the mean distance from the center of the sun. terrestrial planet.
A light year is the distance light travels in one year, while AU, otherwise known as an astronomical unit, is the distance between the sun and the earth. A light year is approximately $9.5 \times {10^{12}}km$. An AU is $149600000km$. As you can probably tell, an AU is much shorter than a light year.
Hence, the correct option is (B) $0.12AU/\min $
So, the correct answer is “Option B”.
Note:
$1672$ the Italian-born French astronomer Gian Domenico Cassini made a reasonably close estimate of the astronomical unit based on a determination of the parallax displacement of the planet Mars-and thus its distance to earth. One of the most important of these is the astronomical unit. It is a unit of length approximating the sun earth distance which is of convenient use in astronomy. Beyond the solar system distance in astronomy are so great that using the au becomes too cumbersome.
Complete step by step answer:
We convert meters to astronomical unit, and seconds to minutes, using
$ 1000m = 1km \\
1AU = 1.50 \times {10^8}km \\
60s = 1\min \\
$
Thus, $3.0 \times {10^8}m/s$becomes
$\left( {\dfrac{{3.0 \times {{10}^8}m}}{8}} \right)\left( {\dfrac{{1km}}{{1000m}}} \right)\left( {\dfrac{{60s}}{{\min }}} \right) = 0.12AU/\min $
Astronomical unit: a unit of measurement equal to $149.6$million kilometers, the mean distance from the center of the sun. terrestrial planet.
A light year is the distance light travels in one year, while AU, otherwise known as an astronomical unit, is the distance between the sun and the earth. A light year is approximately $9.5 \times {10^{12}}km$. An AU is $149600000km$. As you can probably tell, an AU is much shorter than a light year.
Hence, the correct option is (B) $0.12AU/\min $
So, the correct answer is “Option B”.
Note:
$1672$ the Italian-born French astronomer Gian Domenico Cassini made a reasonably close estimate of the astronomical unit based on a determination of the parallax displacement of the planet Mars-and thus its distance to earth. One of the most important of these is the astronomical unit. It is a unit of length approximating the sun earth distance which is of convenient use in astronomy. Beyond the solar system distance in astronomy are so great that using the au becomes too cumbersome.
Recently Updated Pages
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The term ISWM refers to A Integrated Solid Waste Machine class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Which is the longest day and shortest night in the class 11 sst CBSE
In a democracy the final decisionmaking power rests class 11 social science CBSE