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How benzene is converted into benzaldehyde by Gatterman-Koch reaction? Write equations.
Answer
451.8k+ views
Hint:Gatterman-Koch reaction is a reaction by which we can insert formyl group into the aromatic nucleus. Mostly it is used for benzene only but it can also be used in any aromatic compound. A detailed discussion is below. The whole mechanism we should understand in order to convert benzene to benzaldehyde.
Complete answer:
Gatterman-Koch reaction:
Step 1: The first step of the reaction is the generation of the reactive species which can later be utilized to respond on the aromatic ring. Since carbon monoxide goes about as a Lewis base, it can acknowledge a proton from the hydrochloric acid. This outcome is a decidedly charged particle that has diverse resonance structures. One such resonance structure shows a positive charge on the carbon, clarifying the reactivity of the mixture. This species can go about as an electrophile while responding with the aromatic ring. In any case, it is bound to be the objective of a nucleophilic attack from the chloride ion in the hydrochloric acid.
Step 2: When we add a Lewis acid (aluminium chloride), a chloride ion is removed easily from the species. The species now reverts to the reactive form.
Step 3: After that an electrophilic aromatic substitution occurs at the benzene ring. The benzene ring acts as a nucleophile and donates an electron pair to the formal cation. Then the benzene loses its aromatic property but it is quickly dissolved by the proton expulsion.
Thus, by this method the formyl group can easily attach to the benzene ring via the Gatterman – Koch reaction. In the example shown in the above mechanism, benzaldehyde (\[{C_6}{H_5}CHO\]) is formed from the treatment of benzene with carbon monoxide and hydrochloric acid in the presence of aluminium chloride and copper chloride (Catalyst).
Note: This reaction Mechanism begins with the formation of the reactive species with the help of the acid. The overall aim of the reaction is to attach a formyl group (\[ - CHO\]group) to an aromatic system. And also we should keep this in mind that this reaction is not applicable for phenol and phenol ether substrates.
Complete answer:
Gatterman-Koch reaction:
![seo images](https://www.vedantu.com/question-sets/5ea35fde-c533-4dda-ac55-3f6f2ca415973524505544728599979.png)
Step 1: The first step of the reaction is the generation of the reactive species which can later be utilized to respond on the aromatic ring. Since carbon monoxide goes about as a Lewis base, it can acknowledge a proton from the hydrochloric acid. This outcome is a decidedly charged particle that has diverse resonance structures. One such resonance structure shows a positive charge on the carbon, clarifying the reactivity of the mixture. This species can go about as an electrophile while responding with the aromatic ring. In any case, it is bound to be the objective of a nucleophilic attack from the chloride ion in the hydrochloric acid.
Step 2: When we add a Lewis acid (aluminium chloride), a chloride ion is removed easily from the species. The species now reverts to the reactive form.
Step 3: After that an electrophilic aromatic substitution occurs at the benzene ring. The benzene ring acts as a nucleophile and donates an electron pair to the formal cation. Then the benzene loses its aromatic property but it is quickly dissolved by the proton expulsion.
Thus, by this method the formyl group can easily attach to the benzene ring via the Gatterman – Koch reaction. In the example shown in the above mechanism, benzaldehyde (\[{C_6}{H_5}CHO\]) is formed from the treatment of benzene with carbon monoxide and hydrochloric acid in the presence of aluminium chloride and copper chloride (Catalyst).
![seo images](https://www.vedantu.com/question-sets/c2594614-47ab-4691-8d7f-3e3597b555935309072581262759849.png)
Note: This reaction Mechanism begins with the formation of the reactive species with the help of the acid. The overall aim of the reaction is to attach a formyl group (\[ - CHO\]group) to an aromatic system. And also we should keep this in mind that this reaction is not applicable for phenol and phenol ether substrates.
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