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Calculate the mass of ascorbic acid (VitaminC,C6H8O6) to be dissolved in 75g of acetic acid to lower its melting point by 1.5C. Kf=3.9Kkgmol1
Given:
- The formula of ascorbic acid is: C6H8O6
- The mass of acetic acid is: mCH3COOH=75g
- Lowering in the melting point is: ΔTf=1.5C
- The molal depression constant for acetic acid is: Kf=3.9Kkgmol1

Answer
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Hint:
We can use the relationship between the molality of the solution and lowering of freezing point to determine the required mass.

Complete step by step solution:
We know that the numerical value of freezing point is equal to that of melting point as both are the temperature at which liquid and solid states are in equilibrium with each other. So, we can say that the given lowering in the melting point can be taken as depression in freezing point.

For depression in freezing point of a solvent, we have a relationship between the depression in the freezing point and molality of the solution that can be written as follows:
ΔTf=Kfm

Here, ΔTf is the depression in the freezing point of the solvent, Kf is the molal depression constant for the given solvent and m is the molality of the solution.

We can write the molality of a solution in terms of moles of solute (nsolute) and mass of solvent (msolvent) as follows:
m=nsolutemsolventinkg

Let’s rewrite the above expression in terms of masses only as follows:
m=(msolute/Msolute)msolventinkg
Here, Msolute is the molar mass of the solute.

Now we can use the above expression to rewrite equation for depression in the freezing point and molality of the solution as follows:
ΔTf=Kf{(msolute/Msolute)msolventinkg}
Let’s rearrange this equation for mass of solute:
Kf{(msolute/Msolute)msolventinkg}=ΔTf(msolute/Msolute)msolventinkg=ΔTfKf(msolute/Msolute)=(ΔTfKf)×msolventinkgmsolute=(ΔTfKf)×msolventinkg×Msolute

Here, we have ascorbic acid as solute and acetic acid as solvent, so we can write the expression for them:
mC6H8O6=(ΔTfKf)×mCH3COOHinkg×MC6H8O6

Now, let’s convert the units of mass of acetic acid as follows:
mCH3COOH=75g×(1kg1000g)=0.075kg

Finally, we will calculate the required mass of ascorbic acid by substituting values in the derived expression as follows:
mC6H8O6=(1.5K3.9Kkgmol1)×0.075kg×176.12gmol1=5.08g

Hence, the required mass of ascorbic acid is 5.08g.

Note:

We have to keep in mind that depression in freezing point is a change in temperature so it will be the same on the Kelvin scale as well.