Answer
Verified
453k+ views
Hint: In this question we have been asked to calculate the unknown potential V for the given potentiometer circuit. Therefore, to solve this question, we shall first discuss what is a potentiometer briefly. We know that for a balanced point in a potentiometer, the ratio of two emf of a battery is equal to the ratio of lengths. Therefore, we shall use this concept to calculate the unknown potential or emf of the battery.
Formula used: \[V=IR\]
Complete step by step solution:
We know that potentiometer is the electrical device used to compare the emfs of two cells. It is also used to calculate the internal resistance of a cell or measure its potential difference. The balance point is obtained in a potentiometer by connecting one of the batteries between the galvanometer. The jockey is moved until the galvanometer shows no deflection. The length of wire is taken as \[{{l}_{1}}\].
The emf of battery is then given as,
\[{{E}_{1}}=\dfrac{{{l}_{1}}}{L}V\] …………….. (2)
Similarly, when second battery is connected, the emf is given by,
\[{{E}_{2}}=\dfrac{{{l}_{2}}}{L}V\] ………… (1)
Therefore, from (1) and (2) we get,
\[\dfrac{{{E}_{1}}}{{{E}_{2}}}=\dfrac{{{l}_{1}}}{{{l}_{2}}}\].
Now, from the diagram, we know that the resistance given is 290 ohms. This resistor is in series with the wire having 10 ohms resistance. Therefore, the total resistance is
\[R=290+10=300\Omega \]
Therefore, using Ohm's law
We get,
\[V=IR\]
Substituting the given values
We get,
\[3=300\times I\]
Therefore,
\[I={{10}^{-2}}A\] …………… (3)
Now, it is also given that the resistance of 400 cm of wire is 10 ohms.
Therefore, resistance of 240 cm length of wire will be,
\[R=240\times \left( \dfrac{10}{400} \right)\]
\[R=6\Omega \] …………………. (4)
Now, substituting (3) and (4) in Ohm's law
We get,
\[{{V}_{0}}={{10}^{-2}}\times 6\]
Therefore,
\[{{V}_{0}}=0.06V\]
Therefore, the correct answer is option A.
Note: A potentiometer is an electrical device with three-terminal resistors with sliding contact that forms an adjustable voltage divider. The potentiometer acts as the rheostat when only two terminals are used. It is a measuring device used to measure the electric potential of the circuit. Potentiometers are commonly used to control electrical devices such as audio control.
Formula used: \[V=IR\]
Complete step by step solution:
We know that potentiometer is the electrical device used to compare the emfs of two cells. It is also used to calculate the internal resistance of a cell or measure its potential difference. The balance point is obtained in a potentiometer by connecting one of the batteries between the galvanometer. The jockey is moved until the galvanometer shows no deflection. The length of wire is taken as \[{{l}_{1}}\].
The emf of battery is then given as,
\[{{E}_{1}}=\dfrac{{{l}_{1}}}{L}V\] …………….. (2)
Similarly, when second battery is connected, the emf is given by,
\[{{E}_{2}}=\dfrac{{{l}_{2}}}{L}V\] ………… (1)
Therefore, from (1) and (2) we get,
\[\dfrac{{{E}_{1}}}{{{E}_{2}}}=\dfrac{{{l}_{1}}}{{{l}_{2}}}\].
Now, from the diagram, we know that the resistance given is 290 ohms. This resistor is in series with the wire having 10 ohms resistance. Therefore, the total resistance is
\[R=290+10=300\Omega \]
Therefore, using Ohm's law
We get,
\[V=IR\]
Substituting the given values
We get,
\[3=300\times I\]
Therefore,
\[I={{10}^{-2}}A\] …………… (3)
Now, it is also given that the resistance of 400 cm of wire is 10 ohms.
Therefore, resistance of 240 cm length of wire will be,
\[R=240\times \left( \dfrac{10}{400} \right)\]
\[R=6\Omega \] …………………. (4)
Now, substituting (3) and (4) in Ohm's law
We get,
\[{{V}_{0}}={{10}^{-2}}\times 6\]
Therefore,
\[{{V}_{0}}=0.06V\]
Therefore, the correct answer is option A.
Note: A potentiometer is an electrical device with three-terminal resistors with sliding contact that forms an adjustable voltage divider. The potentiometer acts as the rheostat when only two terminals are used. It is a measuring device used to measure the electric potential of the circuit. Potentiometers are commonly used to control electrical devices such as audio control.
Recently Updated Pages
How is abiogenesis theory disproved experimentally class 12 biology CBSE
What is Biological Magnification
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
What are the major means of transport Explain each class 12 social science CBSE
Explain sex determination in humans with the help of class 12 biology CBSE
How much time does it take to bleed after eating p class 12 biology CBSE