Answer
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Hint: Conversion: When a chemical reaction takes place, the process of converting takes place and some potion disappears and is converted to other products. The conversion of $1 - chloropropane$ into the following compounds are simple organic reactions. $1 - chloropropane$ (Also known as n-propyl chloride or$1 - propyl$ $chloride$) is an organic compound. The chemical formula for $1 - chloropropane$ is ${C_3}{H_7}Cl$.
Complete step by step solution:
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into \[1 - iodopropane\].
Now we discuss the conversion of $1 - chloropropane$ into Butane nitrile.
$1 - chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product \[1 - iodopropane\], (chemical formula: ${C_3}{H_7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the reaction of $1 - chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: ${C_4}{H_7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into Propyl ethanoate.
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then \[Propan - 1 - ol\] is treated with propionic acid, chemical formula-${C_3}{H_6}{O_2}$, to give the corresponding product Propyl ethanoate (chemical formula:${C_5}{H_{10}}{O_2}$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1 - chloropropane$ into Propyl ethanoate as,
Therefore, the option A and B is correct.
Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1 - chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1 - chloropropane$.
$1 - chloropropane$ is used in pharmaceutical intermediate for \[n - propylamine\] and solvent for making other chemicals which is also used in pesticides.
Complete step by step solution:
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into \[1 - iodopropane\].
Now we discuss the conversion of $1 - chloropropane$ into Butane nitrile.
$1 - chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product \[1 - iodopropane\], (chemical formula: ${C_3}{H_7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the reaction of $1 - chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: ${C_4}{H_7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into Propyl ethanoate.
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then \[Propan - 1 - ol\] is treated with propionic acid, chemical formula-${C_3}{H_6}{O_2}$, to give the corresponding product Propyl ethanoate (chemical formula:${C_5}{H_{10}}{O_2}$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1 - chloropropane$ into Propyl ethanoate as,
Therefore, the option A and B is correct.
Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1 - chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1 - chloropropane$.
$1 - chloropropane$ is used in pharmaceutical intermediate for \[n - propylamine\] and solvent for making other chemicals which is also used in pesticides.
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