Answer
Verified
440.7k+ views
Hint: Conversion: When a chemical reaction takes place, the process of converting takes place and some potion disappears and is converted to other products. The conversion of $1 - chloropropane$ into the following compounds are simple organic reactions. $1 - chloropropane$ (Also known as n-propyl chloride or$1 - propyl$ $chloride$) is an organic compound. The chemical formula for $1 - chloropropane$ is ${C_3}{H_7}Cl$.
Complete step by step solution:
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into \[1 - iodopropane\].
Now we discuss the conversion of $1 - chloropropane$ into Butane nitrile.
$1 - chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product \[1 - iodopropane\], (chemical formula: ${C_3}{H_7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the reaction of $1 - chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: ${C_4}{H_7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into Propyl ethanoate.
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then \[Propan - 1 - ol\] is treated with propionic acid, chemical formula-${C_3}{H_6}{O_2}$, to give the corresponding product Propyl ethanoate (chemical formula:${C_5}{H_{10}}{O_2}$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1 - chloropropane$ into Propyl ethanoate as,
Therefore, the option A and B is correct.
Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1 - chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1 - chloropropane$.
$1 - chloropropane$ is used in pharmaceutical intermediate for \[n - propylamine\] and solvent for making other chemicals which is also used in pesticides.
Complete step by step solution:
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into \[1 - iodopropane\].
Now we discuss the conversion of $1 - chloropropane$ into Butane nitrile.
$1 - chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product \[1 - iodopropane\], (chemical formula: ${C_3}{H_7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the reaction of $1 - chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: ${C_4}{H_7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,
Now we can discuss the conversion of $1 - chloropropane$ into Propyl ethanoate.
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product \[Propan - 1 - ol\], the chemical formula for \[Propan - 1 - ol\] is ${C_3}{H_7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then \[Propan - 1 - ol\] is treated with propionic acid, chemical formula-${C_3}{H_6}{O_2}$, to give the corresponding product Propyl ethanoate (chemical formula:${C_5}{H_{10}}{O_2}$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1 - chloropropane$ into Propyl ethanoate as,
Therefore, the option A and B is correct.
Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1 - chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1 - chloropropane$.
$1 - chloropropane$ is used in pharmaceutical intermediate for \[n - propylamine\] and solvent for making other chemicals which is also used in pesticides.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Which is the first open university in India A Andhra class 10 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE