Question

Convert 1 - chloropropane into following:
A.$$Propan-1-ol$$
B.$$1-iodopropane$$
C.Butane nitrile
D.Propyl ethanoate

Answer 1

Hint: Conversion: When a chemical reaction takes place, the process of converting takes place and some potion disappears and is converted to other products. The conversion of $1-chloropropane$ into the following compounds are simple organic reactions. $1-chloropropane$ (Also known as n-propyl chloride or$1-propyl$ $chloride$) is an organic compound. The chemical formula for $1-chloropropane$ is $C_3{H}_{7}Cl$.

Complete step by step solution:
When the $1-chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product $$Propan-1-ol$$, the chemical formula for $$Propan-1-ol$$ is $C_3{H}_{7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the conversion of $1-chloropropane$ into $$1-iodopropane$$.
Now we discuss the conversion of $1-chloropropane$ into Butane nitrile.
$1-chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product $$1-iodopropane$$, (chemical formula: $C_3{H}_{7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the reaction of $1-chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: $C_4{H}_{7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the conversion of $1-chloropropane$ into Propyl ethanoate.
When the $1-chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product $$Propan-1-ol$$, the chemical formula for $$Propan-1-ol$$ is $C_3{H}_{7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then $$Propan-1-ol$$ is treated with propionic acid, chemical formula-$C_3{H}_6{O}_2$, to give the corresponding product Propyl ethanoate (chemical formula:$C_5{H}_{10}{O}_2$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1-chloropropane$ into Propyl ethanoate as,

Therefore, the option A and B is correct.

Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1-chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1-chloropropane$.
$1-chloropropane$ is used in pharmaceutical intermediate for $$n-propylamine$$ and solvent for making other chemicals which is also used in pesticides.