Answer
Verified
402.5k+ views
Hint: - (i )In conversion of propene to propan-1-ol, oxidation reaction takes place. Oxidation reaction is the reaction in which oxygen is added to a compound. To convert propene to propan-1-ol, we will use the method of reaction of propene with peroxide.
Complete step-by-step answer:
Reaction of alkene with hydrogen halide in presence of peroxide results Anti Markovnikov’s addition. Anti Markovnikov’s addition states that in reaction of alkene with hydrogen halide, hydrogen is added to the carbon atom of the double bond which is bonded to least number of hydrogen atoms and the halide atom is boned to the another carbon atom of double bond.
The produced alkyl halide reacts with KOH followed by heating produces propan-1-ol.
Note:
The other method to produce propan-1-ol from propene is hydroboration oxidation reaction. In this reaction, reaction of diborane $\left( {{\rm{B}}{{\rm{H}}_{\rm{3}}}} \right)$with propene produces trialkyl boranes (addition product). Then, the oxidation trialkyl boranes to alcohol takes place by ${{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}$(peroxide) in presence of a base $\left( {{\rm{NaOH}}} \right)$.
(ii)
Hint:
In conversion of ethanal to propan-2-ol, the carbon atom increases by one. So, we will use Grignard reagent so, that, parent chain can be increased by one carbon atom.
Complete step-by-step answer:
The reaction of Grignard reagent with carbonyl compounds produces alcohol. We need one more carbon atom than the original reactant. So, we have to use ${\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{MgI}}$ as the Grignard reagent.
Step 1: The nucleophilic attack of Grignard reagent to the carbonyl group produces an adduct.
Step2: Hydrolysis of adduct produces an alcohol.
Note: It is possible to get confused in taking Grignard reagent for the conversion of ethanal to propan-2-ol. You have to observe the number of carbon atoms in reactant and the product. In the given question, one more carbon atom is present in product than the reactant. So, Grignard reagent has only one carbon atom.
Complete step-by-step answer:
Reaction of alkene with hydrogen halide in presence of peroxide results Anti Markovnikov’s addition. Anti Markovnikov’s addition states that in reaction of alkene with hydrogen halide, hydrogen is added to the carbon atom of the double bond which is bonded to least number of hydrogen atoms and the halide atom is boned to the another carbon atom of double bond.
The produced alkyl halide reacts with KOH followed by heating produces propan-1-ol.
Note:
The other method to produce propan-1-ol from propene is hydroboration oxidation reaction. In this reaction, reaction of diborane $\left( {{\rm{B}}{{\rm{H}}_{\rm{3}}}} \right)$with propene produces trialkyl boranes (addition product). Then, the oxidation trialkyl boranes to alcohol takes place by ${{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}$(peroxide) in presence of a base $\left( {{\rm{NaOH}}} \right)$.
(ii)
Hint:
In conversion of ethanal to propan-2-ol, the carbon atom increases by one. So, we will use Grignard reagent so, that, parent chain can be increased by one carbon atom.
Complete step-by-step answer:
The reaction of Grignard reagent with carbonyl compounds produces alcohol. We need one more carbon atom than the original reactant. So, we have to use ${\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{MgI}}$ as the Grignard reagent.
Step 1: The nucleophilic attack of Grignard reagent to the carbonyl group produces an adduct.
Step2: Hydrolysis of adduct produces an alcohol.
Note: It is possible to get confused in taking Grignard reagent for the conversion of ethanal to propan-2-ol. You have to observe the number of carbon atoms in reactant and the product. In the given question, one more carbon atom is present in product than the reactant. So, Grignard reagent has only one carbon atom.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key
JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key
Hybridization of Atomic Orbitals Important Concepts and Tips for JEE
Atomic Structure: Complete Explanation for JEE Main 2025
Trending doubts
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
Collision - Important Concepts and Tips for JEE
Ideal and Non-Ideal Solutions Raoult's Law - JEE
Current Loop as Magnetic Dipole and Its Derivation for JEE
JEE Main 2023 January 30 Shift 2 Question Paper with Answer Keys & Solutions
Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 3 Chemical Kinetics
NCERT Solutions for Class 12 Chemistry In Hindi Chapter 10 Haloalkanes and Haloarenes In Hindi Mediem
Which of the following gem diols is stable A CH3 Cleft class 12 chemistry JEE_Main
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Keys & Solutions