Answer
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Hint: This problem can be solved by drawing a proper diagram and having knowledge about the potential and its properties. Potential is work done per charge to displace from infinite to desire point. Potential difference is work done per charge to displace from one place to another place.
Formula used:
Assume \[W\] work is done on the per Unit charge \[q\] to displace from infinity to desire point is
$V = \dfrac{W}{q}$
If you assume any surface where you choose any two points \[P,Q\]. Potential at that points ${V_P},{V_Q}$ respectively then potential difference
$V = {V_P} - {V_Q}$
Relation between the Electric field \[\left( E \right)\] and electric potential \[\left( V \right)\]
$dE = \dfrac{{dV}}{{dr}}$
Complete step by step answer:
Electric potential:- Amount of work done required on per unit charge to displace from infinity to desired point is called electric potential.
$V = \dfrac{W}{q}$
Let us draw a diagram to understand the problem better.
By this diagram you can observe that every electric field lines situated at particular distance we can say they all are parallel to each other
Then $E = constant$
$dE = 0$
Relation between the Electric field \[\left( E \right)\] and electric potential \[\left( V \right)\]
$dE = \dfrac{{dV}}{{dr}}$
$dV = dE.dr$
dV = 0
V = constant
If change of potential becomes zero it means potential at that surface is constant.
A surface where no work is required to displace the object from one place to another place that surface where every point on the surface has equal potential. This kind of surface is called equipotential surface.
- Two equipotential surfaces never intersect to each other because at the intersection point there is two potential which is not possible.
- Spacing between the surfaces can measure strong and weak potential.
- Potential energy for the first charge will be zero because there is no external repulsive. Another charge is possible to face force of attraction or repulsion.
- This situation will happen when electric fields become constant. Electric fields become constant by uniform displacement between electric field lines.
This surface can be possible
- Dipole charge at the finite distance can make the equipotential surface.
- Two identical positive charges at finite distance can make the equipotential surface.
- Two parallel uniformly charged sheets can make it surface.
Note:
You should have a good knowledge of the Electrostatics concept. You also have to know about the relation of Potential to other electrostatics physical quantities which more visible the situation.
Formula used:
Assume \[W\] work is done on the per Unit charge \[q\] to displace from infinity to desire point is
$V = \dfrac{W}{q}$
If you assume any surface where you choose any two points \[P,Q\]. Potential at that points ${V_P},{V_Q}$ respectively then potential difference
$V = {V_P} - {V_Q}$
Relation between the Electric field \[\left( E \right)\] and electric potential \[\left( V \right)\]
$dE = \dfrac{{dV}}{{dr}}$
Complete step by step answer:
Electric potential:- Amount of work done required on per unit charge to displace from infinity to desired point is called electric potential.
$V = \dfrac{W}{q}$
Let us draw a diagram to understand the problem better.
By this diagram you can observe that every electric field lines situated at particular distance we can say they all are parallel to each other
Then $E = constant$
$dE = 0$
Relation between the Electric field \[\left( E \right)\] and electric potential \[\left( V \right)\]
$dE = \dfrac{{dV}}{{dr}}$
$dV = dE.dr$
dV = 0
V = constant
If change of potential becomes zero it means potential at that surface is constant.
A surface where no work is required to displace the object from one place to another place that surface where every point on the surface has equal potential. This kind of surface is called equipotential surface.
- Two equipotential surfaces never intersect to each other because at the intersection point there is two potential which is not possible.
- Spacing between the surfaces can measure strong and weak potential.
- Potential energy for the first charge will be zero because there is no external repulsive. Another charge is possible to face force of attraction or repulsion.
- This situation will happen when electric fields become constant. Electric fields become constant by uniform displacement between electric field lines.
This surface can be possible
- Dipole charge at the finite distance can make the equipotential surface.
- Two identical positive charges at finite distance can make the equipotential surface.
- Two parallel uniformly charged sheets can make it surface.
Note:
You should have a good knowledge of the Electrostatics concept. You also have to know about the relation of Potential to other electrostatics physical quantities which more visible the situation.
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