Answer
Verified
403.6k+ views
Hint: We will look at the definition of signum function and with the help of that we will plot graph. And then from looking at the graph we can find the value of the domain which will be the values of x for which the function is defined and the range will be the possible values of the function.
Complete step by step solution:
Let’s first look at the definition of signum function.
Signum function is often defined simply as 1 for x > 0 and -1 for x < 0. And for x = 0 it is 0.
$f\left( x \right)=\left\{ \begin{align}
& \frac{\left| x \right|}{x},\text{ if }x\ne 0 \\
& 0,\text{ if }x=0 \\
\end{align} \right.$
$f\left( x \right)=\left\{ \begin{align}
& 1,\text{ if }x>0 \\
& 0,\text{ if }x=0 \\
& -1,\text{ if }x<0\text{ } \\
\end{align} \right.$
Now let’s look at the graph of signum function.
In the graph we can see that point A and B are open, hence these points are not included. So at x = 0, point E is defined and it gives 0.
From the above graph and the given function also we can see that the domain is the value of x for which the function is defined, it is defined for all values of x.
Therefore the domain is $\left( -\infty ,\infty \right)$
The range is the possible value of y, we can see from the graph that the values can be -1, 0, and 1.
Therefore, range is $\left\{ -1,0,1 \right\}$
Note: In the solution we have given two forms of signum function, one can break the value of $\left| x \right|$ for x>0 and x<0, and then put the equation to convert it in the second form. So, one should not be confused with such issues.
Complete step by step solution:
Let’s first look at the definition of signum function.
Signum function is often defined simply as 1 for x > 0 and -1 for x < 0. And for x = 0 it is 0.
$f\left( x \right)=\left\{ \begin{align}
& \frac{\left| x \right|}{x},\text{ if }x\ne 0 \\
& 0,\text{ if }x=0 \\
\end{align} \right.$
$f\left( x \right)=\left\{ \begin{align}
& 1,\text{ if }x>0 \\
& 0,\text{ if }x=0 \\
& -1,\text{ if }x<0\text{ } \\
\end{align} \right.$
Now let’s look at the graph of signum function.
In the graph we can see that point A and B are open, hence these points are not included. So at x = 0, point E is defined and it gives 0.
From the above graph and the given function also we can see that the domain is the value of x for which the function is defined, it is defined for all values of x.
Therefore the domain is $\left( -\infty ,\infty \right)$
The range is the possible value of y, we can see from the graph that the values can be -1, 0, and 1.
Therefore, range is $\left\{ -1,0,1 \right\}$
Note: In the solution we have given two forms of signum function, one can break the value of $\left| x \right|$ for x>0 and x<0, and then put the equation to convert it in the second form. So, one should not be confused with such issues.
Recently Updated Pages
A uniform rod of length L and mass M is pivoted at class 11 physics JEE_Main
A wire of length L and radius r is clamped rigidly class 11 physics JEE_Main
The number of moles of KMnO4 that will be needed to class 11 chemistry JEE_Main
The oxidation process involves class 11 chemistry JEE_Main
A car starts from rest to cover a distance s The coefficient class 11 physics JEE_Main
The transalkenes are formed by the reduction of alkynes class 11 chemistry JEE_Main
Trending doubts
Which is the longest day and shortest night in the class 11 sst CBSE
Who was the Governor general of India at the time of class 11 social science CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
In a democracy the final decisionmaking power rests class 11 social science CBSE