When the dice is rolled what is the probability of getting 2 or 3.
Answer
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Hint: Let us first see what favorable event means.
Favorable event is an event of occurrence desired by an observer.
In our case it is getting 2 or 3 on the visible face of dice after rolling.
As we know probability of event can be calculated with the help of total outcomes and favorable outcomes. We can proceed to solve the given question.
$ P(A) = \dfrac{{occurrence\,\,of\,A}}{{Total\,Events}}$
Complete step-by-step answer:
In our question It is given that a dice is rolled. A dice has 6 faces and is numbered from 1 through 6. These are the random outcomes we can get when we roll a dice. Only one outcome at a time is a desired condition.
This means that one of the numbers will occur each time we roll the dice.
The total number of outcomes are = 6
In our given question it is stated that we require the outcome 2 or 3.
The possibility of outcome 2 and 3 both Is ‘one’.
So favorable outcomes in our case are = 2
So, now we can find out the probability of occurrence of the event.
$
\Pr obability = \dfrac{{Favorable\,Outcomes}}{{Total\,Outcomes}} \\
\Rightarrow \Pr obability = \dfrac{2}{6} \\
\Rightarrow \Pr obability = \dfrac{1}{3} \;
$
Hence, the probability of getting 2 or 3 when dice is rolled is $ \dfrac{1}{3}$
So, the correct answer is “$ \dfrac{1}{3}$”.
Note: Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates surety.
Favorable event is an event of occurrence desired by an observer.
In our case it is getting 2 or 3 on the visible face of dice after rolling.
As we know probability of event can be calculated with the help of total outcomes and favorable outcomes. We can proceed to solve the given question.
$ P(A) = \dfrac{{occurrence\,\,of\,A}}{{Total\,Events}}$
Complete step-by-step answer:
In our question It is given that a dice is rolled. A dice has 6 faces and is numbered from 1 through 6. These are the random outcomes we can get when we roll a dice. Only one outcome at a time is a desired condition.
This means that one of the numbers will occur each time we roll the dice.
The total number of outcomes are = 6
In our given question it is stated that we require the outcome 2 or 3.
The possibility of outcome 2 and 3 both Is ‘one’.
So favorable outcomes in our case are = 2
So, now we can find out the probability of occurrence of the event.
$
\Pr obability = \dfrac{{Favorable\,Outcomes}}{{Total\,Outcomes}} \\
\Rightarrow \Pr obability = \dfrac{2}{6} \\
\Rightarrow \Pr obability = \dfrac{1}{3} \;
$
Hence, the probability of getting 2 or 3 when dice is rolled is $ \dfrac{1}{3}$
So, the correct answer is “$ \dfrac{1}{3}$”.
Note: Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates surety.
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