
Diodes \[D - 1\] and \[{D_2}\] shown in circuit are silicon diodes. The voltage drop (\[V\]) across the diode \[{D_2}\] and the power dissipated (\[P\]) by this diode (\[{D_2}\]) are
Answer
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Hint:First of all, we will analyze the given circuit, to look for the diode which is forward biased and the diode which is reversed biased. In a parallel connection the voltage remains the same in all the elements. However, that does not mean that current remains the same.
Complete answer:
In the given figure, we can see that the diode \[{D_1}\] is forward biased and diode \[{D_2}\] is reversed biased. Since the diode \[{D_1}\] is biased forward the voltage drop across it is \[5\,{\text{V}}\]. Since the \[{D_1}\] and \[{{\text{D}}_2}\] diodes are linked in parallel, the voltage drop across is equal to that across \[{D_1}\], i.e. \[5\,{\text{V}}\].
Since \[{{\text{D}}_2}\] is biased in reverse, no current flows through it and so the power dissipated by \[{{\text{D}}_2}\] is zero. As we know, that power is the product of voltage and current. Since, the current is zero in reversed biased condition, hence power is also zero.
Hence, the required answer is \[{V_{{D_2}}} = 5\,{\text{V}}\] and \[{P_{{D_2}}} = 0\,{\text{W}}\].
Additional information:
Forward bias: The external voltage is delivered through the P-N junction diode by forward bias or biasing. The P-side of the diode is connected to the positive terminal in a forward bias configuration, and the N-side is fixed to the battery's negative side.
Diode: A diode is a semiconductor device that basically functions as a one-way current switch. It makes it possible for current to flow freely in one direction, but seriously limits current from flowing in the opposite direction.
Note:Remember that in an electric circuit, a diode (PN junction) allows current to flow more quickly in one direction than in another. Forward biasing means placing a voltage across a diode that makes it easier for current to pass, while reverse biasing means putting a voltage in the opposite direction across a diode.
Complete answer:
In the given figure, we can see that the diode \[{D_1}\] is forward biased and diode \[{D_2}\] is reversed biased. Since the diode \[{D_1}\] is biased forward the voltage drop across it is \[5\,{\text{V}}\]. Since the \[{D_1}\] and \[{{\text{D}}_2}\] diodes are linked in parallel, the voltage drop across is equal to that across \[{D_1}\], i.e. \[5\,{\text{V}}\].
Since \[{{\text{D}}_2}\] is biased in reverse, no current flows through it and so the power dissipated by \[{{\text{D}}_2}\] is zero. As we know, that power is the product of voltage and current. Since, the current is zero in reversed biased condition, hence power is also zero.
Hence, the required answer is \[{V_{{D_2}}} = 5\,{\text{V}}\] and \[{P_{{D_2}}} = 0\,{\text{W}}\].
Additional information:
Forward bias: The external voltage is delivered through the P-N junction diode by forward bias or biasing. The P-side of the diode is connected to the positive terminal in a forward bias configuration, and the N-side is fixed to the battery's negative side.
Diode: A diode is a semiconductor device that basically functions as a one-way current switch. It makes it possible for current to flow freely in one direction, but seriously limits current from flowing in the opposite direction.
Note:Remember that in an electric circuit, a diode (PN junction) allows current to flow more quickly in one direction than in another. Forward biasing means placing a voltage across a diode that makes it easier for current to pass, while reverse biasing means putting a voltage in the opposite direction across a diode.
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