Question

How does sulfuric acid react with sodium carbonate?

Answer 1

Hint: Sulphuric acid is a strong acid with the molecular formula of $H_{2}S{O}_4$ and sodium carbonate is a base with the molecular formula of $N{a}_{2}C{O}_3$ . The base and acid react and undergo a neutralization reaction by forming salt as one product along with the liberation of carbon dioxide and water.

Complete answer:
Chemical compounds are classified into acids, baes and neutral compounds depending upon the nature. Acids are the compounds that can release a proton one of the examples is sulphuric acid with the molecular formula of $H_{2}S{O}_4$ and bases are the compounds that can be able to abstract a proton, one of the examples is sodium carbonate with a molecular formula of $N{a}_{2}C{O}_3$ .
Acids and bases react with each other to form a corresponding salt along with the liberation of water, as sodium carbonate contains the anion carbonate, decarboxylation also occurs in the reaction. The chemical reaction is known as the neutralization reaction.
Thus, sulphuric acid reacts with sodium carbonate to give sodium sulphate with molecular formula of $N{a}_{2}S{O}_4$ . The other products are carbon dioxide and water.
The chemical reaction involved is as follows:
 $H_{2}S{O}_4+N{a}_{2}C{O}_3\to N{a}_{2}S{O}_4+H_{2}O+C{O}_2$
Thus, in the above reaction, an ionic salt known as sodium sulphate, water and carbon dioxide were evolved.

Note:
Neutralization reaction is one of the reactions where acid and base are reacted with each other to form a corresponding salt. If the base does not contain a carbonate as its anion, then the decarboxylation does not occur. Only the salt and water were the products of the neutralization reaction.