
Each angle of the square is of measure:
A. $120^\circ $
B. $90^\circ $
C. $60^\circ $
D. $180^\circ $
Answer
542.1k+ views
Hint: Here we just need to know the property of the square and here we get that the square's every angle measures the sum of $90^\circ $ and this is also there for the rectangle that each angle is $90^\circ $.
Complete Step by Step Solution:
Here we are given that we need to find each and every angle’s measure in the square. We must know that each angle of the square is equal and we know that the square is made by use of the four line segment and every angle in the square is the same.
We know that square is also a type of quadrilateral. So the sum of all the angles of the quadrilateral is $360^\circ $.
Let each and every angle of the square be $x^\circ $
So we can say that all four angles will be $x^\circ $
Sum$ = 360^\circ $
Hence we can say that:
$x + x + x + x = 360^\circ $
Now we can solve this equation and get the value of $x^\circ $ which is actually the angle of the square.
So we get:
$
4x = 360^\circ \\
x = 90^\circ \\
$
Hence we get each angle of the square as $90^\circ $
Hence B) is the correct option.
Note:
Here we must know the properties of all the quadrilaterals. Square has the diagonals intersecting at $90^\circ $ and also the measure of each angle and side is equal in square. Each angle of the rectangle is also equal to $90^\circ $.
Complete Step by Step Solution:
Here we are given that we need to find each and every angle’s measure in the square. We must know that each angle of the square is equal and we know that the square is made by use of the four line segment and every angle in the square is the same.
We know that square is also a type of quadrilateral. So the sum of all the angles of the quadrilateral is $360^\circ $.
Let each and every angle of the square be $x^\circ $
So we can say that all four angles will be $x^\circ $
Sum$ = 360^\circ $
Hence we can say that:
$x + x + x + x = 360^\circ $
Now we can solve this equation and get the value of $x^\circ $ which is actually the angle of the square.
So we get:
$
4x = 360^\circ \\
x = 90^\circ \\
$
Hence we get each angle of the square as $90^\circ $
Hence B) is the correct option.
Note:
Here we must know the properties of all the quadrilaterals. Square has the diagonals intersecting at $90^\circ $ and also the measure of each angle and side is equal in square. Each angle of the rectangle is also equal to $90^\circ $.
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