
Establish a relation between magnetic permeability and magnetic susceptibility.
Answer
566.1k+ views
Hint: When a magnetic material is placed in a magnetic field the magnetic field inside the magnetic material changes use the relationship how the magnetic field changes inside the magnetic material to find the relation between permeability and magnetic susceptibility.
Complete step by step answer:
When a magnetic material is kept in a magnetising field (H).
Then the total number of magnetic lines of force inside the material =magnetic lines of force due to magnetising field +magnetic lines of force due to magnetization of specimens.
i.e. Magnetic induction(B) = ${B_0}$(no of lines of force sur to H)+${\mu _0}I$(no of lines due to magnetization of specimen)
$
B = {B_0} + {\mu _0}I = {\mu _0}H + {\mu _0}I = {\mu _0}(H + I) \\
\Rightarrow B = {\mu _0}H(1 + {\chi _m})as{\chi _m} = \dfrac{1}{H} \\
$
Now $B = \mu H = {\mu _0}H(1 + {\chi _m}) \Rightarrow \mu = {\mu _0}(1 + {\chi _m})$
${\mu _r} = \dfrac{\mu }{{{\mu _0}}} = 1 + {\chi _m}$
Hence relationship between magnetic permeability and magnetic susceptibility is
${\mu _r} = \dfrac{\mu }{{{\mu _0}}} = 1 + {\chi _m}$.
Note:
As we can see ${\mu _r} = 1 + {\chi _m}$ so if ${\chi _m}$ is positive relative permeability will be greater than 1 and if ${\chi _m}$ is negative then relative permeability will be less than one which is the case of the diamagnetic materials.
Complete step by step answer:
When a magnetic material is kept in a magnetising field (H).
Then the total number of magnetic lines of force inside the material =magnetic lines of force due to magnetising field +magnetic lines of force due to magnetization of specimens.
i.e. Magnetic induction(B) = ${B_0}$(no of lines of force sur to H)+${\mu _0}I$(no of lines due to magnetization of specimen)
$
B = {B_0} + {\mu _0}I = {\mu _0}H + {\mu _0}I = {\mu _0}(H + I) \\
\Rightarrow B = {\mu _0}H(1 + {\chi _m})as{\chi _m} = \dfrac{1}{H} \\
$
Now $B = \mu H = {\mu _0}H(1 + {\chi _m}) \Rightarrow \mu = {\mu _0}(1 + {\chi _m})$
${\mu _r} = \dfrac{\mu }{{{\mu _0}}} = 1 + {\chi _m}$
Hence relationship between magnetic permeability and magnetic susceptibility is
${\mu _r} = \dfrac{\mu }{{{\mu _0}}} = 1 + {\chi _m}$.
Note:
As we can see ${\mu _r} = 1 + {\chi _m}$ so if ${\chi _m}$ is positive relative permeability will be greater than 1 and if ${\chi _m}$ is negative then relative permeability will be less than one which is the case of the diamagnetic materials.
Recently Updated Pages
What is fringe in wave optics class 12 physics CBSE

From a pack of 52 cards 4 are drawn one by one without class 12 maths CBSE

What is conjugate foci Explain class 12 physics CBSE

Give reasons for the following Woodblock print only class 12 social science CBSE

Which signals get disrupted in case of a spinal cord class 12 biology CBSE

EDTA has coordination number A 3 B 4 C 5 D 6 class 12 chemistry CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

