
How do you evaluate $\tan \left( {\arctan \left( {0.88} \right)} \right)$?
Answer
524.1k+ views
Hint: We are given a trigonometric expression. We have to find the value of the expression. First, evaluate the expression inside the brackets. Then, apply the trigonometric property to simplify the expression.
Complete step by step solution:
The given trigonometric expression is $\tan \left( {\arctan \left( {0.88} \right)} \right)$
It can be written as $\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right)$
The inverse of the function is opposite of the trigonometric function. Here, tan and $ta{n^{ - 1}}$ are opposite to each other.
When the function and its inverse is multiplied, then the result of multiplication is 1.
$ \Rightarrow \tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88$
Hence the value of $\tan \left( {\arctan \left( {0.88} \right)} \right)$ is equal to $0.88$.
Note: The students must note that we can also find the value of the given expression using the inverse tangent function data table.
First, the value of $ta{n^{ - 1}}\left( {0.88} \right)$ is determined from the table.
$ \Rightarrow ta{n^{ - 1}}\left( {0.88} \right) = 41.35^\circ $
Now, we will substitute $41.35^\circ $ into the expression, we get:
$ \Rightarrow \tan \left( {41.35^\circ } \right)$
Then, we will determine the value of $\tan \left( {41.35^\circ } \right)$ from the data table.
$ \Rightarrow \tan \left( {41.35^\circ } \right) = 0.88$
Therefore, $\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88$
Complete step by step solution:
The given trigonometric expression is $\tan \left( {\arctan \left( {0.88} \right)} \right)$
It can be written as $\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right)$
The inverse of the function is opposite of the trigonometric function. Here, tan and $ta{n^{ - 1}}$ are opposite to each other.
When the function and its inverse is multiplied, then the result of multiplication is 1.
$ \Rightarrow \tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88$
Hence the value of $\tan \left( {\arctan \left( {0.88} \right)} \right)$ is equal to $0.88$.
Note: The students must note that we can also find the value of the given expression using the inverse tangent function data table.
First, the value of $ta{n^{ - 1}}\left( {0.88} \right)$ is determined from the table.
$ \Rightarrow ta{n^{ - 1}}\left( {0.88} \right) = 41.35^\circ $
Now, we will substitute $41.35^\circ $ into the expression, we get:
$ \Rightarrow \tan \left( {41.35^\circ } \right)$
Then, we will determine the value of $\tan \left( {41.35^\circ } \right)$ from the data table.
$ \Rightarrow \tan \left( {41.35^\circ } \right) = 0.88$
Therefore, $\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88$
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Which prominent US inventor was known as the Wizard class 12 social science CBSE

Which state in India is known as the Granary of India class 12 social science CBSE

Draw a ray diagram of compound microscope when the class 12 physics CBSE

When was the first election held in India a 194748 class 12 sst CBSE

How is democracy better than other forms of government class 12 social science CBSE

