Answer
Verified
392.4k+ views
Hint: We must be having the idea that spectral series is obtained when an atom emits energy while making transition from higher energy level to lower energy level. In a spectral series, there will be different lines which correspond to different amounts of energy released. We should know that a hydrogen atom consists of an electron revolving around the nucleus.
Complete step by step answer:
If we take a hydrogen atom, it contains an electron orbiting around the nucleus which can orbit in different orbits called energy levels. If this electron makes a transition from higher energy level to a lower energy level, it emits energy by means of light. This emitted light will be having different wavelengths which depends on the transition levels. This difference gives rise to a spectrum which is known as emission spectrum of hydrogen atom which consist of different spectral lines corresponding to each transition.
We have Rydberg formula to determine the wavelength of emitted light which is given as,
\[\dfrac{1}{\lambda }=R{{Z}^{2}}\left( \dfrac{1}{{{p}^{2}}}-\dfrac{1}{{{n}^{2}}} \right)\]
Where,\[R\] is the \[\text{Rydberg Constant}=1.09737\times {{10}^{7}}{{m}^{-1}}\]
\[Z\] is the atomic number
\[p\] is lower energy level
\[n\] is higher energy level
If we group the spectral lines appearing in a hydrogen atom, they are of five series.
\[1)\]Lyman series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=2,3,4,5...\]) to the first energy level (\[p=1\]). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
\[2)\]Balmer series:
In this series, spectral lines are obtained by the transition of electrons from any high energy level (\[n=3,4,5,6...\]) to second energy level (\[p=2\]). The wavelength emitted in this series lies in the visible region of the electromagnetic spectrum. The first line in this series (\[n=3\text{ to }p=2\]) is called \[{{H}_{\alpha }}\] line, and the second line (\[n=4\text{ to }p=2\]) is called \[{{H}_{\beta }}\] line.
\[3)\]Paschen series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=4,5,6,7...\]) to the first energy level (\[p=3\]). The wavelength of light emitted in this series lies in the infrared region of the electromagnetic spectrum.
\[4)\]Brackett series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=5,6,7,8...\]) to the first energy level (\[p=4\]). The wavelength of light emitted in this series also lies in the infrared region of the electromagnetic spectrum.
\[5)\]Pfund series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=6,7,8,9...\]) to the first energy level (\[p=5\]). The wavelength of light emitted in this series also lies in the infrared region of the electromagnetic spectrum.
So, this is how the spectral series of a hydrogen atom is explained.
Note:
We must also have some additional information about what a spectrum is. It is the footprint of an atom which will be unique for any given atom. By analyzing a spectrum, we can deduce many properties and characteristics of an unknown sample such as electronic configuration, shape, crystal structure etc. we use different spectroscopic techniques to get the spectrum of a given atom.
Complete step by step answer:
If we take a hydrogen atom, it contains an electron orbiting around the nucleus which can orbit in different orbits called energy levels. If this electron makes a transition from higher energy level to a lower energy level, it emits energy by means of light. This emitted light will be having different wavelengths which depends on the transition levels. This difference gives rise to a spectrum which is known as emission spectrum of hydrogen atom which consist of different spectral lines corresponding to each transition.
We have Rydberg formula to determine the wavelength of emitted light which is given as,
\[\dfrac{1}{\lambda }=R{{Z}^{2}}\left( \dfrac{1}{{{p}^{2}}}-\dfrac{1}{{{n}^{2}}} \right)\]
Where,\[R\] is the \[\text{Rydberg Constant}=1.09737\times {{10}^{7}}{{m}^{-1}}\]
\[Z\] is the atomic number
\[p\] is lower energy level
\[n\] is higher energy level
If we group the spectral lines appearing in a hydrogen atom, they are of five series.
\[1)\]Lyman series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=2,3,4,5...\]) to the first energy level (\[p=1\]). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
\[2)\]Balmer series:
In this series, spectral lines are obtained by the transition of electrons from any high energy level (\[n=3,4,5,6...\]) to second energy level (\[p=2\]). The wavelength emitted in this series lies in the visible region of the electromagnetic spectrum. The first line in this series (\[n=3\text{ to }p=2\]) is called \[{{H}_{\alpha }}\] line, and the second line (\[n=4\text{ to }p=2\]) is called \[{{H}_{\beta }}\] line.
\[3)\]Paschen series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=4,5,6,7...\]) to the first energy level (\[p=3\]). The wavelength of light emitted in this series lies in the infrared region of the electromagnetic spectrum.
\[4)\]Brackett series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=5,6,7,8...\]) to the first energy level (\[p=4\]). The wavelength of light emitted in this series also lies in the infrared region of the electromagnetic spectrum.
\[5)\]Pfund series:
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (\[n=6,7,8,9...\]) to the first energy level (\[p=5\]). The wavelength of light emitted in this series also lies in the infrared region of the electromagnetic spectrum.
So, this is how the spectral series of a hydrogen atom is explained.
Note:
We must also have some additional information about what a spectrum is. It is the footprint of an atom which will be unique for any given atom. By analyzing a spectrum, we can deduce many properties and characteristics of an unknown sample such as electronic configuration, shape, crystal structure etc. we use different spectroscopic techniques to get the spectrum of a given atom.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE