Answer
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Hint: First we will write y in terms of x and then put x = 1 to check whether we get y = 2. After this we will draw the graph of the 3x -2y = 6 on the graph paper. And lastly we will find the value of y at x = 4.
Complete step-by-step answer:
The given equation is:
3x -2y = 6 ---- (1)
Putting the value of x =1 and y = 2, we get:
LHS = $3 \times 1 - 2 \times 2 = 3 - 4 = - 1$ $ \ne $ RHS
So this point doesn’t lie on the line.
y can be expressed in terms of x as follow:
$ \Rightarrow {\text{y = }}\dfrac{{3{\text{x - 6}}}}{2}$
At x = 0,
y = $\dfrac{{3 \times 0 - 6}}{2} = - 3$
At y = 0,
x= $\dfrac{6}{3} = 2$.
The graph of the above equation is as follow:
From the graph, we can say that the value of y at x = 4 is 3 denoted by C(4,3).
Note: In the question involving drawing graphs of a two variable linear equation, you should express the dependent variable in terms of independent variable and then get two points in the XY plane to draw the graph. The slope of the line of the form ax+by = c is given as m= $\dfrac{{ - a}}{b}$.
Complete step-by-step answer:
The given equation is:
3x -2y = 6 ---- (1)
Putting the value of x =1 and y = 2, we get:
LHS = $3 \times 1 - 2 \times 2 = 3 - 4 = - 1$ $ \ne $ RHS
So this point doesn’t lie on the line.
y can be expressed in terms of x as follow:
$ \Rightarrow {\text{y = }}\dfrac{{3{\text{x - 6}}}}{2}$
At x = 0,
y = $\dfrac{{3 \times 0 - 6}}{2} = - 3$
At y = 0,
x= $\dfrac{6}{3} = 2$.
The graph of the above equation is as follow:
From the graph, we can say that the value of y at x = 4 is 3 denoted by C(4,3).
Note: In the question involving drawing graphs of a two variable linear equation, you should express the dependent variable in terms of independent variable and then get two points in the XY plane to draw the graph. The slope of the line of the form ax+by = c is given as m= $\dfrac{{ - a}}{b}$.
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