Figure shows a planet in an elliptical orbit around the Sun S. Where is the kinetic energy of the planet maximum?
A. ${P_1}$
B. ${P_2}$
C. ${P_3}$
D. ${P_4}$
Answer
Verified
456.6k+ views
Hint:Here we have to apply the concept of angular momentum and kinetic energy.In mechanics, angular momentum is the rotational counterpart to linear momentum (rarely, momentum or rotational momentum). In mechanics, it is an important quantity since it is a conserved quantity; a closed system's cumulative angular momentum stays unchanged. In physics, an object's kinetic energy (KE) is the energy it possesses because of its motion. It is defined as the work required in accelerating from rest to the specified velocity of a body of a given mass.
Complete step by step answer:
The angular momentum of rigid bodies is preserved; a rotating object can thus continue to rotate until an outside force acts on it. Angular momentum shifts are torque-equivalent.
Angular momentum is given by:
$L = mvr$
Where $m$ is the mass, $v$ is the velocity and $r$ is the radius.
Angular momentum is conserved, including energy and linear momentum. Another symbol of inherent unity of physical laws is this generally applicable statute. When the net external torque is zero, angular momentum is maintained, just as linear momentum is retained when the net external force is zero. For the angular momentum to be constant, $mvr$ should be equal to constant.
Thus $mvr = {\text{constant}}$
Thus, $v\alpha \dfrac{1}{r}$
So, when the velocity is maximum, radius is minimum as velocity is inversely proportional to the radius. Radius $r$ is minimum at the point ${P_4}$. Here velocity is maximum.
So, kinetic energy, $K.E = \dfrac{1}{2}m{v^2}$
Since, kinetic energy is directly proportional to the velocity. So, kinetic energy is maximum at the point ${P_4}$.
Hence, option D is correct.
Note:Here we have to see that diagram which point is further away from the sun. Otherwise if we write points, then the answer would be wrong. As long as their sum stays continuous, any of the individual angular moments can alter. When the external force on a structure is zero, this law is equivalent to linear momentum being maintained.
Complete step by step answer:
The angular momentum of rigid bodies is preserved; a rotating object can thus continue to rotate until an outside force acts on it. Angular momentum shifts are torque-equivalent.
Angular momentum is given by:
$L = mvr$
Where $m$ is the mass, $v$ is the velocity and $r$ is the radius.
Angular momentum is conserved, including energy and linear momentum. Another symbol of inherent unity of physical laws is this generally applicable statute. When the net external torque is zero, angular momentum is maintained, just as linear momentum is retained when the net external force is zero. For the angular momentum to be constant, $mvr$ should be equal to constant.
Thus $mvr = {\text{constant}}$
Thus, $v\alpha \dfrac{1}{r}$
So, when the velocity is maximum, radius is minimum as velocity is inversely proportional to the radius. Radius $r$ is minimum at the point ${P_4}$. Here velocity is maximum.
So, kinetic energy, $K.E = \dfrac{1}{2}m{v^2}$
Since, kinetic energy is directly proportional to the velocity. So, kinetic energy is maximum at the point ${P_4}$.
Hence, option D is correct.
Note:Here we have to see that diagram which point is further away from the sun. Otherwise if we write points, then the answer would be wrong. As long as their sum stays continuous, any of the individual angular moments can alter. When the external force on a structure is zero, this law is equivalent to linear momentum being maintained.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE
What organs are located on the left side of your body class 11 biology CBSE