Find oxidation number of boron in \[NaB{H_4}\]
Answer
Verified
407.1k+ views
Hint: Boron is a chemical element with atomic number 5 and the letter B. It is a low-abundance element in the Solar System and the Earth's surface, generated entirely by cosmic ray spallation and supernovae rather than stellar nucleosynthesis. It makes up about 0.001% of the Earth's crust by weight.
Complete answer:
In basic terms, the oxidation number is the number assigned to the elements in a chemical mixture. The oxidation number is the total number of electrons that atoms in a molecule will share, lose, or obtain when forming chemical bonds with atoms of another substance.
Rules for Assigning Oxidation Numbers
It is customary to write the action first in a formula, followed by the anion.
A free element's oxidation number is always zero.
The charge of a monatomic ion is equal to its oxidation number.
Hydrogen's oxidation number is typically +1. In materials containing elements that are less electronegative than hydrogen, the oxidation number of hydrogen is -1.
In certain compounds, the oxidation number of oxygen is -2 except in fluorides.
A Group IA member in a compound has an oxidation number of +1.
A Group IIA member in a compound has an oxidation number of +2.
Except when paired with a higher electronegativity factor, the oxidation number of a Group VIIA element in a compound is -1. In HCl, Cl has an oxidation number of -1, but in HOCl, it has an oxidation number of +1.
The oxidation numbers of all the atoms in a neutral substance add up to zero.
The charge of a polyatomic ion is proportional to the sum of its oxidation numbers.
Now in \[NaB{H_4}\]
A Group IA member in a compound has an oxidation number of +1.
Na = + 1
Since this is a metal hydride, hydrogen's oxidation state is - 1.
$H_4 = 4 \times (-1) = -4$
Hence \[NaB{H_4}\] = 1 + x – 4 = 0
X = 3
Oxidation number of Boron = 3
Note:
The inorganic compound sodium borohydride, also known as sodium tetrahydridoborate and sodium tetrahydroborate, has the formula NaBH₄. This white solid, which is generally found as a powder, is a reducing agent used in chemistry, both in the laboratory and on a large scale.
Complete answer:
In basic terms, the oxidation number is the number assigned to the elements in a chemical mixture. The oxidation number is the total number of electrons that atoms in a molecule will share, lose, or obtain when forming chemical bonds with atoms of another substance.
Rules for Assigning Oxidation Numbers
It is customary to write the action first in a formula, followed by the anion.
A free element's oxidation number is always zero.
The charge of a monatomic ion is equal to its oxidation number.
Hydrogen's oxidation number is typically +1. In materials containing elements that are less electronegative than hydrogen, the oxidation number of hydrogen is -1.
In certain compounds, the oxidation number of oxygen is -2 except in fluorides.
A Group IA member in a compound has an oxidation number of +1.
A Group IIA member in a compound has an oxidation number of +2.
Except when paired with a higher electronegativity factor, the oxidation number of a Group VIIA element in a compound is -1. In HCl, Cl has an oxidation number of -1, but in HOCl, it has an oxidation number of +1.
The oxidation numbers of all the atoms in a neutral substance add up to zero.
The charge of a polyatomic ion is proportional to the sum of its oxidation numbers.
Now in \[NaB{H_4}\]
A Group IA member in a compound has an oxidation number of +1.
Na = + 1
Since this is a metal hydride, hydrogen's oxidation state is - 1.
$H_4 = 4 \times (-1) = -4$
Hence \[NaB{H_4}\] = 1 + x – 4 = 0
X = 3
Oxidation number of Boron = 3
Note:
The inorganic compound sodium borohydride, also known as sodium tetrahydridoborate and sodium tetrahydroborate, has the formula NaBH₄. This white solid, which is generally found as a powder, is a reducing agent used in chemistry, both in the laboratory and on a large scale.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Trending doubts
Define least count of vernier callipers How do you class 11 physics CBSE
The combining capacity of an element is known as i class 11 chemistry CBSE
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
Find the image of the point 38 about the line x+3y class 11 maths CBSE
Can anyone list 10 advantages and disadvantages of friction
Distinguish between Mitosis and Meiosis class 11 biology CBSE