Question

Find the first six multiples of 17
    A. $17,\text{ 52, 85, 102, 119}$
    B. $34,\text{76, 102, 119, 340}$
    C. $34,\text{ 51, 68, 102, 170}$
    D. $17,\text{ 34,}\text{51,}\text{68, 85, 102}$

Answer 1

Hint: Multiples are obtained by multiplying the number by the integers. In other words, the multiples of the number are all the numbers that are products of the number and any other natural numbers. For Example – the multiples of $2$ are $2,\text{ 4, 6, 8, 10, 12, 14 , 16}$ and so on... Similarly, Multiple of $17$ will be the numbers which can be divided by the number itself that is $17$without the remainder.


Complete step by step solution
The get the first six multiples of $17$
The first multiple of $17$ is-
Multiply $17$ by $1=\text{17}\times \text{1 = 17}$
Similarly to get the second multiple of$17$,
Multiply $17$ by $2\text{ = 17}\times \text{2 = 34}$
In the same way we can find the third, fourth, fifth and sixth multiples by multiplying $17$ with $3,\text{ 4, 5 and 6}$ respectively.
 Third multiple of $17$ is $=\text{ 17}\times \text{3 = 51}$
Fourth multiple of $17$is $=\text{17}\times \text{4 = 68}$
  Fifth multiple of $17$is $=\text{17}\times 5=\text{85}$
   Sixth multiple of $17$is $=\text{ 17}\times \text{6 = 102}$
Therefore, the first six multiples of $17$are $17,\text{ 34, 51, 68, 85, 102}$
Hence, from the given multiple choices, option D is the correct answer.


Note: A multiple is the resultant of multiplying a number by an integer and never by the fractions. Multiples of the numbers are infinite; there is no end for the multiples of any number. Always remember that the first multiple of any number is the number itself. Every number is the multiple of$1$. Also, $0$(zero) is the multiple of every number. Actually, the multiples are the numbers which you learn in the form of the tables generally till the tenth or twelfth place of every number. When a number is the multiple of $2$ or more numbers then it is called the common multiple of that number.