
General formula of saturated monocarboxylic acid is:
A.${C_n}{H_{2n + 1}}COOH$
B.${C_n}{H_{2n}}{O_2}$
C.Both A and B
D.None of the above
Answer
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Hint: We must remember that in chemistry, the general formula is a sort of empirical formula that represents the composition of a member of an entire class of compounds. And also in chemistry, carbon atoms bonded to at least one another by single covalent bonds only, not at all by more reactive double or triple chemical bonds are known as saturated compounds.
Complete step by step answer:
We need to know that the carboxylic acids are the compounds that consist of the molecule, the carboxyl functional group attached to the hydrocarbon. The carboxyl consists of carbonyl $(C = O)$ with a hydroxyl $(O - H)$ attached to an equivalent atom and is typically written as $ - COOH$ or $C{O_2}H$ .
We know that the saturated carboxylic acids may be aliphatic acids but do not contain carbon-carbon double bonds.
If the compound contains one carboxylic acid it is called monocarboxylic acid and two carboxylic acids are called dicarboxylic acid and so on.
We need to know that $RCOOH$ is general monocarboxylic acid.
Let $R$ be $C{H_3}$ or $H$ then $RCOOH$ is $C{H_3}COOH$ or $HCOOH$ respectively. The general formula for these will be ${C_n}{H_{2n}}{O_2}$ trend.
Let $R$ be ${C_2}{H_5}$ then $RCOOH$ is ${C_2}{H_5}COOH$ . The general formula for this will be ${C_n}{H_{2n + 2}}{O_2}$ trend.
Hence, the general formula of saturated monocarboxylic acid are ${C_n}{H_{2n}}{O_2}$ or ${C_n}{H_{2n + 2}}{O_2}$ .
So, C. both A and B is the correct answer.
Note:
We must need to know that entire fatty acids are carboxylic acids although not all are saturated. Unsaturated acids show chemical attributes familiar of compounds that consist of both a carboxyl group and one or extra carbon-carbon double bond. An Example of unsaturation of carboxylic acid is $C{H_2}CH = CHC{O_2}H$. There stand $\alpha ,\beta - unsaturated acids$, and that the double bond is mid the second and third carbons of the chain. Additionally unsaturated acids, in that the double bond appears in a separate position.
Complete step by step answer:
We need to know that the carboxylic acids are the compounds that consist of the molecule, the carboxyl functional group attached to the hydrocarbon. The carboxyl consists of carbonyl $(C = O)$ with a hydroxyl $(O - H)$ attached to an equivalent atom and is typically written as $ - COOH$ or $C{O_2}H$ .
We know that the saturated carboxylic acids may be aliphatic acids but do not contain carbon-carbon double bonds.
If the compound contains one carboxylic acid it is called monocarboxylic acid and two carboxylic acids are called dicarboxylic acid and so on.
We need to know that $RCOOH$ is general monocarboxylic acid.
Let $R$ be $C{H_3}$ or $H$ then $RCOOH$ is $C{H_3}COOH$ or $HCOOH$ respectively. The general formula for these will be ${C_n}{H_{2n}}{O_2}$ trend.
Let $R$ be ${C_2}{H_5}$ then $RCOOH$ is ${C_2}{H_5}COOH$ . The general formula for this will be ${C_n}{H_{2n + 2}}{O_2}$ trend.
Hence, the general formula of saturated monocarboxylic acid are ${C_n}{H_{2n}}{O_2}$ or ${C_n}{H_{2n + 2}}{O_2}$ .
So, C. both A and B is the correct answer.
Note:
We must need to know that entire fatty acids are carboxylic acids although not all are saturated. Unsaturated acids show chemical attributes familiar of compounds that consist of both a carboxyl group and one or extra carbon-carbon double bond. An Example of unsaturation of carboxylic acid is $C{H_2}CH = CHC{O_2}H$. There stand $\alpha ,\beta - unsaturated acids$, and that the double bond is mid the second and third carbons of the chain. Additionally unsaturated acids, in that the double bond appears in a separate position.
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