Answer
418.2k+ views
Hint: The compounds which are solid in the state have some different properties at equilibrium than the ionic compounds in other states. Here ${K_c}$ is called the equilibrium constant and depends on the concentration of the reactants and products that are in equilibrium in the solution.
${K_{sp}}$ is called the solubility product which is related to the solid solute’s interaction with its saturated solution.
Complete step by step answer:
It is given that the solution is containing an excess of solid silver chloride ( $AgCl(s)$ ). $AgCl$ is in equilibrium in the solution as
The value of solubility product of $AgCl$ is given as ${K_{sp}}\,of\,AgCl = 1.8 \times {10^{ - 10}}\ ,at\,298K$
This means that for solid silver chloride in equilibrium with its saturated solution, the product of silver and chloride ions is equal to its solubility product.
In the saturated solution, the concentration of the two ions will be equal to the molar solubility of silver chloride.
Thus, assuming the molar solubility of silver chloride as $S$ we get
$[A{g^ + }] = [C{l^ - }] = S$
So the solubility product can be written as
${K_{sp}} = [A{g^ + }][C{l^ - }]$
$\Rightarrow {K_{sp}} = S \times S = {S^2}$
Equating the actual value given in the question we get
${S^2} = 1.8 \times {10^{ - 10}}$
$\Rightarrow S = 1.34 \times {10^{ - 5}}$
So we can say that $[A{g^ + }] = S = 1.34 \times {10^{ - 5}}M$
Now considering the equilibrium equation given in the question above
We are given its equilibrium constant, ${K_c} = 6.2 \times {10^{ - 8}}$
Writing the equilibrium constant equation for the above equation we get
${K_c} = \dfrac{{[A{g^ + }]{{[N{H_3}]}^2}}}{{{{[Ag{{(N{H_3})}_2}]}^ + }}}$
Therefore, upon cross multiplying we get
Concentration of the complex = $\dfrac{{[A{g^ + }]{{[N{H_3}]}^2}}}{{{K_c}}} $
$\Rightarrow$ Concentration of the complex = $\dfrac{{1.34 \times {{10}^{ - 5}} \ times {{(1)}^2}}}{{6.2 \times {{10}^{ - 8}}}}$
$\Rightarrow$ Concentration of the complex = 216.13
SSo the Concentration of the complex is 216.13 $M$
Note: Some ionic solids vary greatly when it comes to the solubility in a solution. Some salts like calcium chloride are so soluble that they absorb water from the atmosphere others like lithium fluoride are insoluble.
The solvation and saturation depend on the lattice enthalpy of the solute and the solvation enthalpy of the ions in the solution. For the salt to dissolve in the solvent the lattice energy of the salt must be overcome by the ion-ion interaction of the solute and solvent molecules.
${K_{sp}}$ is called the solubility product which is related to the solid solute’s interaction with its saturated solution.
Complete step by step answer:
It is given that the solution is containing an excess of solid silver chloride ( $AgCl(s)$ ). $AgCl$ is in equilibrium in the solution as
The value of solubility product of $AgCl$ is given as ${K_{sp}}\,of\,AgCl = 1.8 \times {10^{ - 10}}\ ,at\,298K$
This means that for solid silver chloride in equilibrium with its saturated solution, the product of silver and chloride ions is equal to its solubility product.
In the saturated solution, the concentration of the two ions will be equal to the molar solubility of silver chloride.
Thus, assuming the molar solubility of silver chloride as $S$ we get
$[A{g^ + }] = [C{l^ - }] = S$
So the solubility product can be written as
${K_{sp}} = [A{g^ + }][C{l^ - }]$
$\Rightarrow {K_{sp}} = S \times S = {S^2}$
Equating the actual value given in the question we get
${S^2} = 1.8 \times {10^{ - 10}}$
$\Rightarrow S = 1.34 \times {10^{ - 5}}$
So we can say that $[A{g^ + }] = S = 1.34 \times {10^{ - 5}}M$
Now considering the equilibrium equation given in the question above
We are given its equilibrium constant, ${K_c} = 6.2 \times {10^{ - 8}}$
Writing the equilibrium constant equation for the above equation we get
${K_c} = \dfrac{{[A{g^ + }]{{[N{H_3}]}^2}}}{{{{[Ag{{(N{H_3})}_2}]}^ + }}}$
Therefore, upon cross multiplying we get
Concentration of the complex = $\dfrac{{[A{g^ + }]{{[N{H_3}]}^2}}}{{{K_c}}} $
$\Rightarrow$ Concentration of the complex = $\dfrac{{1.34 \times {{10}^{ - 5}} \ times {{(1)}^2}}}{{6.2 \times {{10}^{ - 8}}}}$
$\Rightarrow$ Concentration of the complex = 216.13
SSo the Concentration of the complex is 216.13 $M$
Note: Some ionic solids vary greatly when it comes to the solubility in a solution. Some salts like calcium chloride are so soluble that they absorb water from the atmosphere others like lithium fluoride are insoluble.
The solvation and saturation depend on the lattice enthalpy of the solute and the solvation enthalpy of the ions in the solution. For the salt to dissolve in the solvent the lattice energy of the salt must be overcome by the ion-ion interaction of the solute and solvent molecules.
Recently Updated Pages
Mark and label the given geoinformation on the outline class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
When people say No pun intended what does that mea class 8 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Name the states which share their boundary with Indias class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give an account of the Northern Plains of India class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Advantages and disadvantages of science
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Bimbisara was the founder of dynasty A Nanda B Haryanka class 6 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
10 examples of evaporation in daily life with explanations
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How do you graph the function fx 4x class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)