Answer
409.8k+ views
Hint: The molecular formula for cyclopropane is ${C_3}{H_6}$ and its molar mass is $42.08g/mol$
Since $\vartriangle {H_{comb}} = - 4000kJmo{l^{ - 1}} Thus, 42.08g$ of cyclopropane has the heat of $ - 4000kJ$.
Complete step by step answer:
Combustion is the chemical process in which a substance reacts rapidly with oxygen and librates the heat. The reactant involved is called fuel and the source of oxygen is called oxidiser. During combustion, the fuel and oxidant react with each other forming different compounds. When cyclopropane undergoes combustion, it breaks down to form water and carbon dioxide with the liberation of energy and the combustion of one mole of cyclopropane can be written as, ${C_3}{H_6} + \dfrac{9}{2}{O_2} \to 3C{O_2} + 3{H_2}O + 4000kJ$
Since $\vartriangle {H_{comb}} = - 4000kJmo{l^{ - 1}}$ and thus, the reaction is exothermic.
Thus, one mole of cyclopropane liberates the heat of $4000kJ$
It is known that one mole of cyclopropane contains $42.08g$ Therefore, $42.08g$ of cyclopropane liberates the heat of $4000kJ$
Let “x” be the amount of cyclopropane that needs to be burnt in oxygen for producing $ 2 \times {10^5}kJ$ of heat.
It is known that the molecular formula for cyclopropane is ${C_3}{H_6}$ and it has three carbons and six hydrogens. Therefore, its molar mass is $42.08g/mol$
The amount of cyclopropane that needs to be burnt in oxygen for producing $2 \times {10^5}kJ$ of heat can be written as follows,
$x = \dfrac{{42.08g/mol \times 2 \times {{10}^5}kJ}}{{4000kJmo{l^{ - 1}}}}$
$x = 0.021 \times {10^5}g$
$x = 0.021 \times {10^5} \times {10^{ - 3}}kg$
$x = 0.021 \times {10^2}kg$
$x = 2.1kg$
Hence, the correct option is B.
Note: The heat of combustion will be negative since the heat is liberated and the reaction follows an exothermic process.
When we calculate the amount of cyclopropane that needs to be burnt in oxygen for producing $2 \times {10^5}kJ$ of heat, a negative sign is not needed since mass can’t be negative.
Since $\vartriangle {H_{comb}} = - 4000kJmo{l^{ - 1}} Thus, 42.08g$ of cyclopropane has the heat of $ - 4000kJ$.
Complete step by step answer:
Combustion is the chemical process in which a substance reacts rapidly with oxygen and librates the heat. The reactant involved is called fuel and the source of oxygen is called oxidiser. During combustion, the fuel and oxidant react with each other forming different compounds. When cyclopropane undergoes combustion, it breaks down to form water and carbon dioxide with the liberation of energy and the combustion of one mole of cyclopropane can be written as, ${C_3}{H_6} + \dfrac{9}{2}{O_2} \to 3C{O_2} + 3{H_2}O + 4000kJ$
Since $\vartriangle {H_{comb}} = - 4000kJmo{l^{ - 1}}$ and thus, the reaction is exothermic.
Thus, one mole of cyclopropane liberates the heat of $4000kJ$
It is known that one mole of cyclopropane contains $42.08g$ Therefore, $42.08g$ of cyclopropane liberates the heat of $4000kJ$
Let “x” be the amount of cyclopropane that needs to be burnt in oxygen for producing $ 2 \times {10^5}kJ$ of heat.
It is known that the molecular formula for cyclopropane is ${C_3}{H_6}$ and it has three carbons and six hydrogens. Therefore, its molar mass is $42.08g/mol$
The amount of cyclopropane that needs to be burnt in oxygen for producing $2 \times {10^5}kJ$ of heat can be written as follows,
$x = \dfrac{{42.08g/mol \times 2 \times {{10}^5}kJ}}{{4000kJmo{l^{ - 1}}}}$
$x = 0.021 \times {10^5}g$
$x = 0.021 \times {10^5} \times {10^{ - 3}}kg$
$x = 0.021 \times {10^2}kg$
$x = 2.1kg$
Hence, the correct option is B.
Note: The heat of combustion will be negative since the heat is liberated and the reaction follows an exothermic process.
When we calculate the amount of cyclopropane that needs to be burnt in oxygen for producing $2 \times {10^5}kJ$ of heat, a negative sign is not needed since mass can’t be negative.
Recently Updated Pages
Mark and label the given geoinformation on the outline class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
When people say No pun intended what does that mea class 8 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Name the states which share their boundary with Indias class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give an account of the Northern Plains of India class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Advantages and disadvantages of science
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Bimbisara was the founder of dynasty A Nanda B Haryanka class 6 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
10 examples of evaporation in daily life with explanations
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How do you graph the function fx 4x class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)