
What happens when
(i) Chlorobenzene is treated with
(ii) Ethyl chloride is treated with
(iii) 2-bromopentane is treated with alcoholic KOH?
Write the chemical equation in support of your answer.
Answer
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Hint: In the first reaction, when chlorobenzene reacts with , it will undergo nucleophilic substitution reaction and give multiple products.
In the second reaction, Ethyl chloride is reacted with . This reaction is the Victor Mayer method.
In the third reaction, 2-bromopentane is treated with alcoholic KOH, will follow Saytzeff’s rule and undergo elimination.
Complete step by step answer:
(i) When Chlorobenzene is treated with , it will lead to the formation of both ortho and para isomers. The ortho isomer will be 1,2-Dichlorobenzene and the para isomer will be 1,4-Dichlorobenzene. The reaction is given below
(ii) When Ethyl chloride, is treated with Silver Nitrite, it will lead to the formation of Nitroethane and white precipitate of Silver chloride, . This process is known as Victor Meyer Method.
(iii) When 2-bromopentane is treated with alcoholic KOH it will follow Saytzeff’s rule and will undergo elimination. This reaction will give two products. Among that one will be major and the other will be minor. The major product in this reaction is Pent-2-ene and the minor product will be Pent-1-ene.
Therefore,
(i) When Chlorobenzene is treated with , it will give 1,2-Dichlorobenzene and 1,4-Dichlorobenzene.
(ii) When Ethyl chloride is treated with , it will give Nitroethane.
(iii) When 2-bromopentane is treated with alcoholic KOH, it will give Pent-2-ene as the major product and Pent-1-ene as the minor product.
Note: According to the Saytzeff’s rule, when dehydrohalogenation reaction takes place and the most stable product will be that alkene i.e., 2-pentene, which has largely substituted alkene group in it. The less substituted alkene will be the minor product and also called the Hofmann product.
In the second reaction, Ethyl chloride is reacted with
In the third reaction, 2-bromopentane is treated with alcoholic KOH, will follow Saytzeff’s rule and undergo
Complete step by step answer:
(i) When Chlorobenzene is treated with

(ii) When Ethyl chloride,

(iii) When 2-bromopentane is treated with alcoholic KOH it will follow Saytzeff’s rule and will undergo

Therefore,
(i) When Chlorobenzene is treated with
(ii) When Ethyl chloride is treated with
(iii) When 2-bromopentane is treated with alcoholic KOH, it will give Pent-2-ene as the major product and Pent-1-ene as the minor product.
Note: According to the Saytzeff’s rule, when dehydrohalogenation reaction takes place and the most stable product will be that alkene i.e., 2-pentene, which has largely substituted alkene group in it. The less substituted alkene will be the minor product and also called the Hofmann product.
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