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Hofmann degradation of m- Bromo benzamide gives :
a.) aniline
b.) m- bromoaniline
c.) bromobenzene
d.) m- Bromo ethyl benzene


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Answer
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Hint: The Hofmann degradation reaction is used to convert primary amide to a primary amine. The general Hofmann’s Bromo amide reaction may be written as -
$RCON{H_2} + B{r_2} + KOH \to RN{H_2}$


Complete answer:
First, let us see what is the Hofmann degradation reaction. This is the reaction to convert primary amide to a primary amine. The general Hofmann’s Bromo amide reaction may be written as -
$RCON{H_2} + B{r_2} + KOH \to RN{H_2}$
So, the reaction of m- Bromo benzamide may be written as -
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So, the Hofmann degradation of m- Bromo benzamide can give aniline.

Thus, the correct answer is the option a.).

Additional information:
In this reaction, one carbon atom decreases in the product. The reaction of bromine with potassium hydroxide forms potassium hypobromite that converts the primary amide into isocyanate intermediate. This intermediate is then hydrolysed to primary amine and the carbon dioxide is also formed along with the product. The sodium hydroxide can also be used in place of potassium hydroxide. It also reacts in a similar way. The bromine can also be substituted by many other reagents. Such as - Sodium hypochlorite, lead tetraacetate, N- Bromosuccinimide etc. could also be used.

Note: It has various applications. It is used to convert the aliphatic and aromatic both types of amides into amines. It is used in the preparation of anthranilic acid from phthalimide. By using this reaction, the Nicotinic acid can also be converted into 3- Aminopyridine.