How do you find the cube root of 64?
Answer
Verified
449.1k+ views
Hint:
First we need to find the factors of the given number to calculate the cube root. Factors are the number which completely divide the number without leaving any remainder behind. the cube root of a $\sqrt[3]{{64}}$ can be calculated by prime factorization of the number. Prime factorization is defined as expressing a number as a product of prime numbers. The numbers which are divisible by 1 and itself, i.e., it should only have two factors called prime numbers.
Complete step by step solution:
Given the number to simplify is $\sqrt[3]{{64}}$
First we will find the cube root of $64$ by finding its prime factors. Cube root of a number can be simplified by prime factorization of the number.
Prime factorization involves expressing a number as a product of prime numbers.
The prime factor of $64$
$
2|64 \\
2|32 \\
2|16 \\
2|8 \\
2|4 \\
2 \\
$
Hence the factor of $\left( {64} \right) = 2 \times 2 \times 2 \times 2 \times 2 \times 2$
Now we will pair the similar factors in a group of two,
Therefore,
$
\Rightarrow \sqrt[3]{{64}} = \sqrt[3]{{{2^6}}} \\
\Rightarrow \sqrt[3]{{64}} = {2^{\dfrac{6}{3}}} \\
$
After forming a pair of the similar factors, we will take a pair out of the cube root and thus, continue this process to simplify and attain the answer.
$ \Rightarrow \sqrt[3]{{64}} = {2^2} = 4$
Hence, we get the cube root of $64$ is $4$
Note:
Cube root of any number is calculated by prime factorization of the number. After prime factorization which involves expressing a number as a product of prime numbers (numbers which are divisible by and itself), we need to pair the similar factors in a group of two. Another way to simplify the cube root of any number is using the long division method, which is quite complex, and thus, the chances of getting any error is high.
First we need to find the factors of the given number to calculate the cube root. Factors are the number which completely divide the number without leaving any remainder behind. the cube root of a $\sqrt[3]{{64}}$ can be calculated by prime factorization of the number. Prime factorization is defined as expressing a number as a product of prime numbers. The numbers which are divisible by 1 and itself, i.e., it should only have two factors called prime numbers.
Complete step by step solution:
Given the number to simplify is $\sqrt[3]{{64}}$
First we will find the cube root of $64$ by finding its prime factors. Cube root of a number can be simplified by prime factorization of the number.
Prime factorization involves expressing a number as a product of prime numbers.
The prime factor of $64$
$
2|64 \\
2|32 \\
2|16 \\
2|8 \\
2|4 \\
2 \\
$
Hence the factor of $\left( {64} \right) = 2 \times 2 \times 2 \times 2 \times 2 \times 2$
Now we will pair the similar factors in a group of two,
Therefore,
$
\Rightarrow \sqrt[3]{{64}} = \sqrt[3]{{{2^6}}} \\
\Rightarrow \sqrt[3]{{64}} = {2^{\dfrac{6}{3}}} \\
$
After forming a pair of the similar factors, we will take a pair out of the cube root and thus, continue this process to simplify and attain the answer.
$ \Rightarrow \sqrt[3]{{64}} = {2^2} = 4$
Hence, we get the cube root of $64$ is $4$
Note:
Cube root of any number is calculated by prime factorization of the number. After prime factorization which involves expressing a number as a product of prime numbers (numbers which are divisible by and itself), we need to pair the similar factors in a group of two. Another way to simplify the cube root of any number is using the long division method, which is quite complex, and thus, the chances of getting any error is high.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
When people say No pun intended what does that mea class 8 english CBSE
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
How many ounces are in 500 mL class 8 maths CBSE
Which king started the organization of the Kumbh fair class 8 social science CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Advantages and disadvantages of science