Answer
Verified
435.3k+ views
Hint:
We know the general equation of a straight line is $y = mx + c$ where $m$ is the gradient and $y = c$ is the value where the line cuts the $y - $ axis. We know about the cartesian coordinates of points which is $(x,y)$ where $x$ is the abscissa and $y$ is the ordinate.
Complete step by step Solution:
Given that – line equation is $y = - x$
Now we will put values of $x = 0,1,2,3......$ in above equation one by one and get the value of $y$
Now we will put value $x = 0$in $y = - x$ , we get $y = 0$
Now we will put value $x = 1$ in $y = - x$ , we get $y = - 1$
Now we will put value $x = 2$ in $y = - x$ , we get $y = - 2$
Now we will put value $x = 3$ in $y = - x$ , we get $y = - 3$
Now we will put value $x = 4$ in $y = - x$ , we get $y = - 4$
We got enough points for representing a line of given linear equation $y = - x$ on the graph
Now we will put all point on the graph which we got by putting values of $x$ in equation $y = - x$ which are $(0,0),(1, - 1),(2, - 2),(3, - 3),(4, - 4)$
The above graph is the required graph for the given line $y = - x$
Note:
We know that general equation of line is $y = mx + c$ we can solve above given equation $y = - x$ also by comparing it with $y = mx + c$ then we will get $m = - 1$ then this means that the slope of given line is the below of $x - axis$ axis and right side of $y - axis$.
We know the general equation of a straight line is $y = mx + c$ where $m$ is the gradient and $y = c$ is the value where the line cuts the $y - $ axis. We know about the cartesian coordinates of points which is $(x,y)$ where $x$ is the abscissa and $y$ is the ordinate.
Complete step by step Solution:
Given that – line equation is $y = - x$
Now we will put values of $x = 0,1,2,3......$ in above equation one by one and get the value of $y$
Now we will put value $x = 0$in $y = - x$ , we get $y = 0$
Now we will put value $x = 1$ in $y = - x$ , we get $y = - 1$
Now we will put value $x = 2$ in $y = - x$ , we get $y = - 2$
Now we will put value $x = 3$ in $y = - x$ , we get $y = - 3$
Now we will put value $x = 4$ in $y = - x$ , we get $y = - 4$
We got enough points for representing a line of given linear equation $y = - x$ on the graph
Now we will put all point on the graph which we got by putting values of $x$ in equation $y = - x$ which are $(0,0),(1, - 1),(2, - 2),(3, - 3),(4, - 4)$
The above graph is the required graph for the given line $y = - x$
Note:
We know that general equation of line is $y = mx + c$ we can solve above given equation $y = - x$ also by comparing it with $y = mx + c$ then we will get $m = - 1$ then this means that the slope of given line is the below of $x - axis$ axis and right side of $y - axis$.
Recently Updated Pages
A wire of length L and radius r is clamped rigidly class 11 physics JEE_Main
For which of the following reactions H is equal to class 11 chemistry JEE_Main
For the redox reaction MnO4 + C2O42 + H + to Mn2 + class 11 chemistry JEE_Main
In the reaction 2FeCl3 + H2S to 2FeCl2 + 2HCl + S class 11 chemistry JEE_Main
One mole of a nonideal gas undergoes a change of state class 11 chemistry JEE_Main
A stone is projected with speed 20 ms at angle 37circ class 11 physics JEE_Main
Trending doubts
Which is the longest day and shortest night in the class 11 sst CBSE
Who was the Governor general of India at the time of class 11 social science CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
State and prove Bernoullis theorem class 11 physics CBSE