
How do you solve ?
Answer
403.5k+ views
Hint: Here in this question, we have to solve the given equation and it is in the form of an algebraic equation having a variable x. Solving this equation, we have to find the unknown value x by using the basic arithmetic operation like multiplication and division.
Complete step by step answer:
The given equation is an algebraic equation. The algebraic equation is a combination of variable and constant and which has an equal sign. So we use arithmetic operations and solve it further.
Now consider the given equation
Subtract 5 from both sides of the equation.
On simplification, we get
Now divide the above equation both side by 2, then we get
Hence, it’s a required solution.
We can also verify the given question by substituting the value of x.
Consider . Substitute the value of x as , so we have
On simplification we get
Hence LHS is equal to RHS.
Note: There are three methods to solve linear equations in one variable:
1. Trial and error
2. Inverse Operations
3. Transposition method
If the algebraic expression contains only one unknown, we determine the value by using simple arithmetic operations.
Complete step by step answer:
The given equation is an algebraic equation. The algebraic equation is a combination of variable and constant and which has an equal sign. So we use arithmetic operations and solve it further.
Now consider the given equation
Subtract 5 from both sides of the equation.
On simplification, we get
Now divide the above equation both side by 2, then we get
Hence, it’s a required solution.
We can also verify the given question by substituting the value of x.
Consider
On simplification we get
Hence LHS is equal to RHS.
Note: There are three methods to solve linear equations in one variable:
1. Trial and error
2. Inverse Operations
3. Transposition method
If the algebraic expression contains only one unknown, we determine the value by using simple arithmetic operations.
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