Answer
Verified
430.5k+ views
Hint: In this question, we have an equation. Which have two sides’ left-hand side and right-hand side. First we take the left hand side and solve it.to solve the left hand side we used a formula and formula is given as below.
\[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\]
By using the above formula we solve the left hand side, and then we write the left hand side is equal to the right hand side. After that we find the value of\[x\].
Complete step by step answer:
In this question we have given an equation that is,
\[{\left( {x - 3} \right)^2} = 36\]
First, we take the left hand side from the above equation and want to solve it.
Then, the left hand side is.
\[{\left( {x - 3} \right)^2}\]
We know that, \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\]
Then above the left hand side is written as below.
\[
{\left( {x - 3} \right)^2} \\
= {x^2} + {3^2} - 2\times 3\times x \\
= {x^2} + 9 - 6x \\
\]
Now we write that the right left hand side is equal to the right hand side.
Then,
\[ \Rightarrow {x^2} + 9 - 6x = 36\]
We take \[36\] on the left hand side and on the right hand side.
Then,
Above equation is written as below.
\[ \Rightarrow {x^2} + 9 - 6x - 36 = 0\]
We solve the above equation.
\[{x^2} - 6x - 27 = 0\]
The above equation is a quadratic equation. We solve this equation for the value of\[x\].
Then,
\[
\Rightarrow {x^2} - 6x - 27 = 0 \\
\Rightarrow {x^2} + 3x - 9x - 27 = 0 \\
\]
We take the \[x\]is common in the first two and \[ - 9\]is common in the last two.
Then,
\[
x\left( {x + 3} \right) - 9\left( {x + 3} \right) = 0 \\
\left( {x + 3} \right)\left( {x - 9} \right) = 0 \\
\]
Then,
\[
x + 3 = 0 \\
\therefore x = - 3 \\
\]
And,
\[
x - 9 = 0 \\
\therefore x = 9 \\
\]
Therefore, the values of \[x\] are \[ - 3\] and \[9\].
Note:
In this question, an equation of \[x\] is given, which I want to solve. An equation is defined as it has two things which are equal. And the equation also likes a statement “this equal that”. The equation has two things or two sides, the left side is known as the left hand side and the right side is known as the right hand side. The left-hand side is denoted as “LHS” and the right hand side is denoted as “RHS”.
\[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\]
By using the above formula we solve the left hand side, and then we write the left hand side is equal to the right hand side. After that we find the value of\[x\].
Complete step by step answer:
In this question we have given an equation that is,
\[{\left( {x - 3} \right)^2} = 36\]
First, we take the left hand side from the above equation and want to solve it.
Then, the left hand side is.
\[{\left( {x - 3} \right)^2}\]
We know that, \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\]
Then above the left hand side is written as below.
\[
{\left( {x - 3} \right)^2} \\
= {x^2} + {3^2} - 2\times 3\times x \\
= {x^2} + 9 - 6x \\
\]
Now we write that the right left hand side is equal to the right hand side.
Then,
\[ \Rightarrow {x^2} + 9 - 6x = 36\]
We take \[36\] on the left hand side and on the right hand side.
Then,
Above equation is written as below.
\[ \Rightarrow {x^2} + 9 - 6x - 36 = 0\]
We solve the above equation.
\[{x^2} - 6x - 27 = 0\]
The above equation is a quadratic equation. We solve this equation for the value of\[x\].
Then,
\[
\Rightarrow {x^2} - 6x - 27 = 0 \\
\Rightarrow {x^2} + 3x - 9x - 27 = 0 \\
\]
We take the \[x\]is common in the first two and \[ - 9\]is common in the last two.
Then,
\[
x\left( {x + 3} \right) - 9\left( {x + 3} \right) = 0 \\
\left( {x + 3} \right)\left( {x - 9} \right) = 0 \\
\]
Then,
\[
x + 3 = 0 \\
\therefore x = - 3 \\
\]
And,
\[
x - 9 = 0 \\
\therefore x = 9 \\
\]
Therefore, the values of \[x\] are \[ - 3\] and \[9\].
Note:
In this question, an equation of \[x\] is given, which I want to solve. An equation is defined as it has two things which are equal. And the equation also likes a statement “this equal that”. The equation has two things or two sides, the left side is known as the left hand side and the right side is known as the right hand side. The left-hand side is denoted as “LHS” and the right hand side is denoted as “RHS”.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE