Identify the correct option
According to $CIP$ sequence rule, the correct arrangement in order of decreasing priority is:
A. $ - OH > C{H_2}OH > - CHO > - COOH$
B. $ - OH > COOH > - CHO > - C{H_2}OH$
C. $ - COOH > OH > - COH > - C{H_2}OH$
D. $COOH > - CHO > - C{H_2}OH > - OH$
Answer
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Hint:
The higher the atomic number of the immediate substituent atom, the higher the priority.
For example:
$H - < C - < N - < O - < Cl - $
Complete step by step answer:
-The $CIP$ rule is a standard process used in organic chemistry to completely and unequivocally name a stereoisomer of a molecule.
-Priority is numerically assigned as $1,2,3$ and $4$ where smaller the number higher will be the priority. So, $1$ has the highest priority and $4$ has the lowest priority.
Rules for giving the priority:
Rule$1$: Atoms having greater atomic number is given more priority
$ - OH \Rightarrow \,\,{\text{First}}$
Atomic number of ${\text{0}}$ is $8$.
Rule $2$: If ${1^{st}}$ atom is the same then, see ${2^{nd}}$ atom and apply Rule $1$.
Rule $3$: For multiple bond
I
II
Break multiple bonds and add one more same atom to that. After this apply Rule$1$ and Rule $2$.
So, the answer is $ - OH > COOH > - CHO > - C{H_2}OH$
This is the decreasing priority order.
Multiple bonds are treated as separate single bonds.
Note: $ - CH = O$ is given priority over $ - C{H_2}OH$
$I > Br > Cl$
$OH > N{O_2} > N{H_2} > COOH > CHO > C{H_2}$
In geometric isomers:
$Z - {\text{isomer > }}E - {\text{isomer}}$
The higher the atomic number of the immediate substituent atom, the higher the priority.
For example:
$H - < C - < N - < O - < Cl - $
Complete step by step answer:
-The $CIP$ rule is a standard process used in organic chemistry to completely and unequivocally name a stereoisomer of a molecule.
-Priority is numerically assigned as $1,2,3$ and $4$ where smaller the number higher will be the priority. So, $1$ has the highest priority and $4$ has the lowest priority.
Rules for giving the priority:
Rule$1$: Atoms having greater atomic number is given more priority
$ - OH \Rightarrow \,\,{\text{First}}$
Atomic number of ${\text{0}}$ is $8$.
Rule $2$: If ${1^{st}}$ atom is the same then, see ${2^{nd}}$ atom and apply Rule $1$.
Rule $3$: For multiple bond
I
II
Break multiple bonds and add one more same atom to that. After this apply Rule$1$ and Rule $2$.
So, the answer is $ - OH > COOH > - CHO > - C{H_2}OH$
This is the decreasing priority order.
Multiple bonds are treated as separate single bonds.
Note: $ - CH = O$ is given priority over $ - C{H_2}OH$
$I > Br > Cl$
$OH > N{O_2} > N{H_2} > COOH > CHO > C{H_2}$
In geometric isomers:
$Z - {\text{isomer > }}E - {\text{isomer}}$
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